嗨，我是编程的初学者，但有一些基本的了解。 我试图做一个python脚本，给出一个像这样的cpp文件：
///////////////////////////////////
// experimentOrientVertices.cpp
// (modifying square.cpp)
//
// Sumanta Guha.
///////////////////////////////////
#ifdef __APPLE__
# include <GL/glew.h>
# include <GL/freeglut.h>
# include <OpenGL/glext.h>
#else
# include <GL/glew.h>
# include <GL/freeglut.h>
# include <GL/glext.h>
#pragma comment(lib, "glew32.lib")
#endif
// Drawing routine.
void drawScene(void)
{
glClear(GL_COLOR_BUFFER_BIT);
glColor3f(0.0, 0.0, 0.0);
// Draw a polygon with specified vertices.
glPolygonMode(GL_FRONT, GL_LINE);
glPolygonMode(GL_BACK, GL_FILL);
glBegin(GL_POLYGON);
glVertex3f(20.0, 20.0, 0.0);
glVertex3f(80.0, 20.0, 0.0);
glVertex3f(80.0, 80.0, 0.0);
glVertex3f(20.0, 80.0, 0.0);
glEnd();
/*
glPolygonMode(GL_FRONT, GL_LINE);
glPolygonMode(GL_BACK, GL_FILL);
glBegin(GL_POLYGON);
glVertex3f(20.0, 80.0, 0.0);
glVertex3f(20.0, 20.0, 0.0);
glVertex3f(80.0, 20.0, 0.0);
glVertex3f(80.0, 80.0, 0.0);
glEnd();
*/
/*
glPolygonMode(GL_FRONT, GL_LINE);
glPolygonMode(GL_BACK, GL_FILL);
glBegin(GL_POLYGON);
glVertex3f(80.0, 80.0, 0.0);
glVertex3f(80.0, 20.0, 0.0);
glVertex3f(20.0, 20.0, 0.0);
glVertex3f(20.0, 80.0, 0.0);
glEnd();
*/
glFlush();
}
// Initialization routine.
void setup(void)
{
glClearColor(1.0, 1.0, 1.0, 0.0);
}
// OpenGL window reshape routine.
void resize(int w, int h)
{
glViewport(0, 0, w, h);
glMatrixMode(GL_PROJECTION);
glLoadIdentity();
glOrtho(0.0, 100.0, 0.0, 100.0, -1.0, 1.0);
glMatrixMode(GL_MODELVIEW);
glLoadIdentity();
}
// Keyboard input processing routine.
void keyInput(unsigned char key, int x, int y)
{
switch(key)
{
case 27:
exit(0);
break;
default:
break;
}
}
// Main routine.
int main(int argc, char **argv)
{
glutInit(&argc, argv);
glutInitContextVersion(4, 3);
glutInitContextProfile(GLUT_COMPATIBILITY_PROFILE);
glutInitDisplayMode(GLUT_SINGLE | GLUT_RGBA);
glutInitWindowSize(500, 500);
glutInitWindowPosition(100, 100);
glutCreateWindow("experimentOrientVertices.cpp");
glutDisplayFunc(drawScene);
glutReshapeFunc(resize);
glutKeyboardFunc(keyInput);
glewExperimental = GL_TRUE;
glewInit();
setup();
glutMainLoop();
}
应该输出：
[['21=>59']]
[['63=>65']]
[['69=>76']]
[['80=>89'], ['82=>88']]
[['93=>113']]
这就是问题，下面的脚本输出：
[['21=>59']]
[['63=>65'], ['65=>63']]
[['69=>76'], ['76=>69']]
[['80=>89'], ['82=>88'], ['88=>82'], ['89=>80']]
[['93=>113'], ['113=>93']]
而且......我真的无法弄明白这一点 谢谢你的时间，我希望能把这个问题写好！
这是我的剧本：
from sys import argv
token = {
'{': 0
}
level = ["" for i in range(10)]
funcStartStop = [] #list to store each function start and stop brackets value
def functionCount(filename):
inFile = open(filename, 'r')
currLine = 0
mbracketopenline = [] #list to store the currLine value if a { is found
mbracketcloseline = [] #list to store the currLine value if a } is found
first = True
for line in inFile:
currLine += 1
if "{" in line:
token["{"] += 1
if first:
first = False
mbracketopenline.append(currLine)
if "}" in line:
token["{"] -= 1
mbracketcloseline.append(currLine)
if not first and token["{"] == 0:
first = True
tmpfuncStartStop = []
for i in range(mgraffeopenline.__len__()):
tmpfuncStartStop.append([str(str(mbracketopenline[i])+"=>"+str(mbracketcloseline[-i-1]))]) #store opening and
#closing brackets in a list of list, so at the end of the cycle
#should be something like: [['1=>10'],['3=>8']]
funcStartStop.append(tmpfuncStartStop)
mbracketcloseline = mbracketopenline = []
if __name__ == '__main__':
functionCount(argv[1])
for i in funcStartStop:
print(i)
答案 0 :(得分：0)
忽略在您为SO调整示例时所产生的代码错误（例如mgraffeopenline而不是mbracketopenline，functionCount()没有返回结果等），您有以下几点：< / p>
mbracketcloseline = mbracketopenline = []
有效地将mbracketcloseline和mbracketopenline设置为相同的新列表，每当您修改每个列表时，您都要修改相同的列表。这主要是导致您的问题的原因，但还有其他人需要考虑。
另外，正如我在评论中所述，在同一行上有多个括号是完全有效的，你需要考虑它们（包括它们的位置），所以你实际上需要逐个字符地查看你的代码并拿起每一个事件，例如：
def function_count(source):
result = []
progress = [] # a temporary list to keep our progress
level = -1 # we'll use an index to reference the level we're at
with open(source, "r") as f: # open the `source` file for reading
for i, line in enumerate(f): # enumerate and read the file line by line
# you can check `if "{" in line or "}" in line: ...` for a marginal speed-up
for char in line: # iterate over the characters in each line
if char == "{":
if level == -1: # we're at the root, start a root level
progress = []
result.append(progress)
progress.append([i + 1, None]) # store the line # at the level's start
level += 1 # increase the level
elif char == "}":
if level > -1: # if we're already deep in the source tree...
progress[level][1] = i + 1 # store the line # at the level's end
level -= 1 # decrease the level
return result
您的文件产生：
[[[21, 59]],
[[63, 65]],
[[69, 76]],
[[80, 89], [82, 88]],
[[93, 113]]]
但是如果您要将keyInput功能更改为：
void keyInput(unsigned char key, int x, int y)
{ switch(key) {
case 27:
exit(0);
break;
default:
break;
}}
它仍然会产生有效的结果：
[[[21, 59]],
[[63, 65]],
[[69, 76]],
[[80, 86], [80, 86]],
[[90, 110]]]
如果你想在你的例子中打印它（我发现实际的行索引分离得更有用），只需替换该行：
progress[level][1] = i + 1 # store the line # at the level's end
使用：
progress[level] = "{}=>{}".format(progress[level][0], i + 1)
但是，这并没有解决zvone提到的问题，你可以在注释，宏，字符串中使用大括号......所有这些都将被选为函数的有效开始/结束。除了简单的字符匹配之外，代码解析器还有很多。
如果您真的想深入研究解析C代码，那么有一个非常有用的模块pycparser就是为此而设计的。设置可能需要更长的时间，但它会提供比这种深入解析更多的代码洞察力。当然，这一切都取决于你的实际用例......