Question

我正在尝试为每个CSR登录数小时。

我尝试运行以获取数据的查询是：

SELECT  T1.user_log_id,
        T1.[user], 
        min(T1.event_date) AS Date1, 
        max(T2.event_date) AS Date2, 
       DATEDIFF(hour, T1.event_date, T2.event_date) AS DaysDiff
FROM    leads.dbo.lds_User_log T1
        JOIN leads.dbo.lds_User_log  T2
            ON T1.user_log_id = T2.user_log_id
            --AND T2.event_date >= T1.event_date
WHERE T1.event_date between '2018-05-18 00:00:01' AND '2018-05-18 23:00:01' 
GROUP BY T1.user_log_id, T1.event_Date, T2.event_date, T1.[user];

并生成：

在表格中我们有：

老实说，我不知道如何将数据输入到自身中以从DB中提取LOGIN和LOGOUT事件以正确运行DATEDIFF，并且合法丢失。

Answer 1

您遇到的问题是您正在计算组中使用的元素的最大值或分钟数。您应该从组中删除它们。如果你不能使用Date1＆amp; diff中的Date2变量，这取决于您执行此查询的数据库，您无法通过在FROM和JOIN中使用预先计算的表来尝试它。

您可以尝试以下解决方案：

SELECT  T1.user_log_id,
        T1.[user], 
        min(T1.event_date) AS Date1, 
        max(T2.event_date) AS Date2, 
       DATEDIFF(hour, Date1, Date2) AS DaysDiff
FROM    leads.dbo.lds_User_log T1
        JOIN leads.dbo.lds_User_log  T2
            ON T1.user_log_id = T2.user_log_id
WHERE T1.event_date between '2018-05-18 00:00:01' AND '2018-05-18 23:00:01' 
GROUP BY T1.user_log_id, T1.[user];

如果变量不能在同一个选择中使用，则无法通过这种方式解决：

SELECT  T1.user_log_id,
        T1.[user], 
        T1.MinEventDate,
        T2.MaxEventDate,
       DATEDIFF(hour, T1.MinEventDate, T2.MaxEventDate) AS DaysDiff
FROM    (SELECT user_log_id,[user],min(event_date) as MinEventDate 
            FROM leads.dbo.lds_User_log
            WHERE event_date between '2018-05-18 00:00:01' AND '2018-05-18 23:00:01' 
            GROUP BY user_log_id,[user]) T1
        JOIN (SELECT user_log_id,[user],max(event_date) as MaxEventDate 
            FROM leads.dbo.lds_User_log
            WHERE event_date between '2018-05-18 00:00:01' AND '2018-05-18 23:00:01' 
            GROUP BY user_log_id,[user]) T2
            ON T1.user_log_id = T2.user_log_id
GROUP BY T1.user_log_id, T1.[user];

希望这有帮助！

SQL：同一列中日期的日期差异

1 个答案: