Question

我正在尝试json Schema验证Ref：https://wilddiary.com/validate-json-against-schema-in-java/

data.json在下面。 Validator根据模式检查并处理值类型。

但是，如果我尝试将propertyname id更改为iddiff，那么json仍然有效，尽管我期待一个无法识别的字段iddiff错误。我也尝试过其他库。有什么指针吗？

{
    "id": 1,
    "name": "A green door",
    "price": 12.50,
    "tags": ["home", "green"]
}

Answer 1

请尝试以下链接。这个参考很简单，也很有帮助。 http://www.baeldung.com/introduction-to-json-schema-in-java

Answer 2

添加到您的架构：“additionalProperties”：false

{
  "$schema": "http://json-schema.org/draft-04/schema#",
  "title": "Product",
  "description": "A product from Acme's catalog",
  "type": "object",
  "properties": {
    "id": {
      "description": "The unique identifier for a product",
      "type": "integer"
    },
    ....
      "minItems": 1,
      "uniqueItems": true
    }
  },
  "required": ["id", "name", "price"],
  "additionalProperties": false
}

Doc. for more information.

JSON模式验证不能按预期使用PropertyName

2 个答案: