Question

我有一个动作，如果status返回404，则调用一些api，我想从catch返回它。我直接在反应组件中调用此操作，但不从操作中恢复它。

行动

const someAction = (tagId, token) => dispatch => {
dispatch({
        type: TagAssignmentActionTypes.TagAssignmentChanged,
    })

    let status, assignee, response
    try {
        response = await DeviceApi.checkTagAssignment(tagId, token)

        assignee = response.result.assignee
        status = response.result.status
        return response.result
    } catch (e) {
        console.log(e, 'eeeeeeee')
        if (e && e.status === httpStatusCode.notFound)
            status = TagStatus.NotFound
        return status
    }

    dispatch({
        type: TagAssignmentActionTypes.TagAssignmentChanged,
        status,
        assignee,
        response,
    })
}

反应组件中的

功能

 lookupComplete = (tagId = this.state.tagId) => this.setState({tagId}, async () => {

        let person, status
        let result = await this.props.someAction(parseInt(tagId, 16), this.props.accessToken)

        console.log(result.status, 'status')
        status = result.status

        person = this.props.persons[result.assignee]

        person
            ? this.triggerTransition(transitions.ClickCheckTag, {person, status}) : this.triggerTransition(transitions.Free)
    })

如果出现错误，如何从catch返回状态？

Answer 1

在您的try语句中，您需要检查状态是否等于404，然后抛出错误。然后你的catch语句就会执行。

        try {
            response = await DeviceApi.checkTagAssignment(tagId, token);
            assignee = response.result.assignee
            status = response.result.status; 
            if (status === httpStatusCode.notFound){
             var error404 = { 
               message: "not found", 
               status: httpStatusCode.notFound 
             };
             throw error404 ;
           } else {
             return response.result;
           }
        }

Throw statement documentation

如何从redux action中的catch返回

1 个答案: