Question

以下代码摘自较大的程序;无法丢弃一个 - 总是（0,4） - 在16种可能性中：对所有可能性应用相同的逻辑。完全莫名其妙。谢谢你的帮助。

#!/usr/bin/env python3
def mystery():
    #dict generated from a 4x4 array of tkinter canvas rectangles
    geo = {1: (1, 1), 2: (1, 2), 3: (1, 3), 4: (1, 4),
           5: (2, 1), 6: (2, 2), 7: (2, 3), 8: (2, 4),
           9: (3, 1), 10: (3, 2), 11: (3, 3), 12: (3, 4),
           13: (4, 1), 14: (4, 2), 15: (4, 3), 16: (4, 4)}
    #the next two lines needed to get at the key from the values index,
    #to generate a dictionary of neighbours ... used later in the program
    geo_k = list(geo.keys())            #(list of keys)
    geo_v = list(geo.values())          #(list of values)
    #print(geo_v)
    counter = 0
    for k in geo:
        id = geo[k]
        poss_n = [(id[0],id[1]-1),(id[0],id[1]+1),  # possible neighbours
                  (id[0]-1,id[1]),(id[0]+1,id[1])]
        # print("initial ", poss_n)
        for each in poss_n:
            if each not in geo_v:
                print(each)
                counter += 1
                poss_n.remove(each)
            else: pass
        # print("final ", poss_n)
    print(counter)

mystery()

Answer 1

虽然元素拥有for循环，但您无法将其从列表中删除，我建议您按照for each in poss_n[:]的方式执行某些操作，这将创建列表的副本供您迭代同时仍允许您从原始元素中删除元素。

无法消除Python for循环中的条目

1 个答案: