String替换数组PHP中的所有项

Question

我想在数组中的所有项目中进行字符串替换。我所拥有的是：

$row['c1'] = str_replace("&", "&", $row['c1']);
$row['c2'] = str_replace("&", "&", $row['c2']);
$row['c3'] = str_replace("&", "&", $row['c3']);
$row['c4'] = str_replace("&", "&", $row['c4']);   
$row['c5'] = str_replace("&", "&", $row['c5']);
$row['c6'] = str_replace("&", "&", $row['c6']);
$row['c7'] = str_replace("&", "&", $row['c7']);   
$row['c8'] = str_replace("&", "&", $row['c8']);
$row['c9'] = str_replace("&", "&", $row['c9']);
$row['c10'] = str_replace("&", "&", $row['c10']); 

如何用更少的代码实现这一目标？我认为foreach声明会起作用，例如：

$columns = array($row['c1'], $row['c2'], $row['c3'], $row['c4'], $row['c5'], $row['c6'], $row['c7'], $row['c8'], $row['c9'], $row['c10']);

foreach ( $columns as $value){
   $value   = str_replace("&", "&", $value);
}

但它不起作用。

Answer 1

只是做：

$row = str_replace("&", "&", $row);

注意：您的foreach不起作用，因为您需要参考或使用密钥：

foreach ( $columns as &$value) { // reference
   $value  = str_replace("&", "&", $value);
}
unset($value); // break the reference with the last element

或者：

foreach ($columns as $key => $value){
   $columns[$key]  = str_replace("&", "&", $value);
}

虽然这里没有必要，因为str_replace接受并返回数组。

Answer 2

您应该通过引用来调用它，否则foreach会创建$value

的副本

foreach ( $columns as &$value)

Answer 3

另一个解决方案是使用PHP array_walk，如下所示：

function custom_replace( &$item, $key ) {
   $item = str_replace('22', '75', $item);
} 

// Init dummy array.
$columns = array('Cabbage22', 'Frid22ay', 'Internet', 'Place22', '22Salary', '22Stretch', 'Whale22Inn');

// Print BEFORE.
echo 'Before: ';
print_r($columns);

// Make the replacements.
array_walk($columns, 'custom_replace');

// Print AFTER.
echo 'After:';
print_r($columns);

输出：

Before: Array
(
    [0] => Cabbage22
    [1] => Frid22ay
    [2] => Internet
    [3] => Place22
    [4] => 22Salary
    [5] => 22Stretch
    [6] => Whale22Inn
)
After: Array
(
    [0] => Cabbage75
    [1] => Frid75ay
    [2] => Internet
    [3] => Place75
    [4] => 75Salary
    [5] => 75Stretch
    [6] => Whale75Inn
)