Question

我正在开发一个python程序，它会分析用户输入的两张卡片。有（根据研究）你可以获得前两张牌的169种不同的可能性，没有特定的套装。例如，如果他们是同一套装，那么ace和国王一起是第3对，但如果有不同的套装则是第5对。

以下是我的代码现在的样子：

    suit = str(input("suit 1"))
    rank = int(input("rank 1"))
    suit1 = str(input("suit 2"))
    rank1 = int(input("rank 2")) 

if rank == rank1:
    if rank and rank1 == 13: # double ace
        print("1/169")
    elif rank and rank1 == 12: # double king
        print("2/169")
    elif rank and rank1 == 11: # double queen
        print("3/169")
    elif rank and rank1 == 10: # double jack
        print("5/169")
    elif rank and rank1 == 9: # double 10s
        print("10/169")
    elif rank and rank1 == 8: # double 9s
        print("17/169")
    elif rank and rank1 == 7: # double 8s
        print("21/169")
    elif rank and rank1 == 6: # double 7s
        print("29/169")
    elif rank and rank1 == 5: # double 6s
        print("36/169")
    elif rank and rank1 == 4: # double 5s
        print("46/169")
    elif rank and rank1 == 3: # double 4s
        print("50/169")
    elif rank and rank1 == 2: # double 3s
        print("52/169")
    elif rank and rank1 == 1: # double 2s
        print("51/169")

然后基本上同样的东西与不同的西装和排名。显然这不是最好的方法，而且我不是最好的Python编码器，但还有其他更有效的方法吗？

Answer 1

您的代码可以运行，但我们可以通过编写更少的代码和代码来改进它，这些代码和代码可以更容易地复制到pocker的其余组合中。试试这个：

suit = str(input("suit 1"))
rank = int(input("rank 1"))
suit1 = str(input("suit 2"))
rank1 = int(input("rank 2"))

scoring_of_doubles = [ [1,51], [2,52], [3,50], [4,46], [5,36], [6,29], [7,21], [8,17], [9,10], [10,5], [11,3], [12,2], [13,1] ]

if rank == rank1:
    for sublist in scoring_of_doubles:            
        if sublist[0] == rank:
            print("You've got a double, scored at: ")
            print(sublist[1])

Answer 2

我建议您使用dict来保持组织有序：

output = {1: 51,
          2: 52,
          3: 50,
          4: 46,
          5: 36,
          6: 29,
          7: 21,
          8: 17,
          9: 10,
          10: 5,
          11: 3,
          12: 2,
          13: 1}

if rank == rank1:
    print("{}/169".format(output[rank]))

分析扑克中的前2张牌

2 个答案: