我有以下问题,我在数组中生成了站点地图的网址。因此该阵列有60000个条目。谷歌希望我创建2个站点地图,因为每个站点地图的限制是50000个条目。
我怎么能用PHP制作这个?我试过了,但是循环停止并输入另一个文件中的其他数据有问题。这是我的代码sofar。
// $data is array with the urls
$count_array = count($data);
$maxlinksinsitemap = 50000;
$numbersofsitemap = ceil($count_array / $maxlinksinsitemap);
for($i = 1; $i <= $numbersofsitemap; $i++) {
$cfile = "sitemap_" .$i . ".xml";
$createfile = fopen($cfile, 'w');
$creat = "<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n";
$creat .= "<urlset xmlns=\"http://www.sitemaps.org/schemas/sitemap/0.9\"\n";
$creat .= "xmlns:image=\"http://www.sitemaps.org/schemas/sitemap-image/1.1\"\n";
$creat .= "xmlns:video=\"http://www.sitemaps.org/schemas/sitemap-video/1.1\">\n";
$creat .= "<url>\n";
$creat .= "<loc>http://www.urltosite.com</loc>\n";
$creat .= "<priority>1.00</priority>\n";
$creat .= "</url>\n";
$creat .= "</urlset>";
fwrite($createfile, $creat);
fclose($createfile);
}
我需要动态解决方案,
感谢您的帮助。
答案 0 :(得分:3)
array_chunk
是你的朋友:
$data = array_chunk($data, 50000);
foreach ($data as $key => $value)
{
$cfile = 'sitemap_' . $i . '.xml';
$createfile = fopen($cfile, 'w');
fwrite($createfile, "<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n");
fwrite($createfile, "<urlset xmlns=\"http://www.sitemaps.org/schemas/sitemap/0.9\"\n");
fwrite($createfile, "xmlns:image=\"http://www.sitemaps.org/schemas/sitemap-image/1.1\"\n");
fwrite($createfile, "xmlns:video=\"http://www.sitemaps.org/schemas/sitemap-video/1.1\">\n");
foreach ($value as $url)
{
$creat = "<url>\n";
$creat .= "<loc>" . $url . "</loc>\n";
$creat .= "<priority>1.00</priority>\n";
$creat .= "</url>\n";
fwrite($createfile, $creat);
}
fclose($createfile);
}
使用开箱即用的可变数量的站点地图。
答案 1 :(得分:0)
$count_array = count($data);
$i = 0;
foreach ($data as $entry) {
if ($i == 0) {
// code here to start first file
} else if ($i % 50000 == 0) {
// code here to end previous file and start next file
}
// write entry to current file
// insert code here....
// increment counter
$i++;
}
// code here to end last file