Question

当我点击图书链接时，他会重新加载页面并对列进行排序。我想用ajax停止重装,,,怎么样？

这是我对这个过程的作用。

这个getBook函数

public function getBooks($start = 0, $limit = 2, $order = "ASC")
{
   $sql_start = $start * $limit;
   $sql_limit = $limit;
   $sql_order_by = $order;

   $query = "SELECT Library.nameOfBook, userBook.book_id, userBook.user_id FROM loginUser JOIN userBook JOIN Library ON userBook.user_id = loginUser.id AND userBook.book_id = Library.id WHERE loginUser.username=:username ORDER BY Library.nameOfBook $sql_order_by LIMIT $sql_start, $sql_limit";
   $statment = $this->db->prepare($query);
   $statment->execute([
       ':username' => $this->username
   ]);
   $result = $statment->fetchAll();

  echo "<table id='myTable' border='1'>

  <tr>
   <th><a id='sorter' href='#'>Books</a></th>
   <th>Action</th>
   </tr>";
   foreach($result as $row){
       echo "<tr>";
       echo "<td>" . $row['nameOfBook'] . "</td>";
       echo "<td>" ."<input type='submit' id='delete".$row['book_id']."-".$row['user_id']."' onclick='deleteBook(this)' name='delete' value='Delete'>" . "</td>";
       echo "</tr>";
    }

   echo "</table>";
   echo "";
   return count($result);
 }

这个jquery函数

<script>
  $(document).ready(function() {
  $( "#sorter" ).click(function() {
    var order_by_value = $('input[name="order_by"]').val();
    if(order_by_value == "ASC"){
        $('input[name="order_by"]').val("DESC");
    }
    else {
        $('input[name="order_by"]').val("ASC");
    }
    $('input[name="current"]').trigger('click');
 });

 });
</script>

Answer 1

<script>
  $(document).ready(function() {
  $( "#sorter" ).click(function() {
    var order_by_value = $('input[name="order_by"]').val();

$.ajax({
                type: 'GET',
                url: 'the url link ',
                data: {
                    'order_by_value': order_by_value         
       },
                success: function (res) {
                    if(res == "ASC"){
                          $('input[name="order_by"]').val("ASC");
                     }
                    else {
                          $('input[name="order_by"]').val("DSC");
                         }
                    $('input[name="current"]').trigger('click');
                 });
                }
        });

</script>

Answer 2

首先，在确定ajax已完成其过程之前，请不要重新加载页面。

其次，如果您希望在完成提交表单中的表单或数据后使用JS运行该代码。

以下是您在竞争中重新加载页面的ajax代码如何显示

$.ajax({
                type: 'GET',
                url: 'your_page_link.php',//this will be url of your backend page
                data: {
                    'name':name
                    'email':email            
                },// if you are using form then just use .serialize() to submit the form instead of preparing data like this use $("#form_id").serialize()
                success: function (msg) {
                    resp = msg;
                }
        }).done(function(){
             if(resp == your_expected_response){
              window.location.href = "http://stackoverflow.com";
             }else{
              //your error handler
             }
        });

希望这会有所帮助，请随时询问是否需要澄清..

干杯!!

php中的jquery ajax停止重新加载页面

2 个答案: