我使用this answer中的代码创建了以下文件
callpython.c
#include </usr/include/python2.7/Python.h>
int
main(int argc, char *argv[])
{
PyObject *pName, *pModule, *pDict, *pFunc;
PyObject *pArgs, *pValue;
int i;
if (argc < 3) {
fprintf(stderr,"Usage: call pythonfile funcname [args]\n");
return 1;
}
Py_Initialize();
pName = PyString_FromString(argv[1]);
/* Error checking of pName left out */
//fprintf(stderr,"pName is %s\n", pName);
PyRun_SimpleString("import sys");
PyRun_SimpleString("sys.path.append(\".\")");
//PySys_SetArgv(argc, argv);
pModule = PyImport_Import(pName);
Py_DECREF(pName);
if (pModule != NULL) {
pFunc = PyObject_GetAttrString(pModule, argv[2]);
/* pFunc is a new reference */
if (pFunc && PyCallable_Check(pFunc)) {
pArgs = PyTuple_New(argc - 3);
for (i = 0; i < argc - 3; ++i) {
pValue = PyInt_FromLong(atoi(argv[i + 3]));
if (!pValue) {
Py_DECREF(pArgs);
Py_DECREF(pModule);
fprintf(stderr, "Cannot convert argument\n");
return 1;
}
/* iValue reference stolen here: */
PyTuple_SetItem(pArgs, i, pValue);
//PyTuple_SetItem(pArgs, i, argv[i + 3]);
}
pValue = PyObject_CallObject(pFunc, pArgs);
Py_DECREF(pArgs);
if (pValue != NULL) {
printf("Result of call: %ld\n", PyInt_AsLong(pValue));
Py_DECREF(pValue);
}
else {
Py_DECREF(pFunc);
Py_DECREF(pModule);
PyErr_Print();
fprintf(stderr,"Call failed\n");
return 1;
}
}
else {
if (PyErr_Occurred())
PyErr_Print();
fprintf(stderr, "Cannot find function \"%s\"\n", argv[2]);
}
Py_XDECREF(pFunc);
Py_DECREF(pModule);
}
else {
PyErr_Print();
fprintf(stderr, "Failed to load \"%s\"\n", argv[1]);
return 1;
}
Py_Finalize();
return 0;
}
我在helloWorld.py所在的目录中创建了另一个文件。这个python脚本的内容是
def helloworldFunc(a):
print 'Hello '+str(a)
我编译并运行callpython.c,如下所示
g++ -o callpython callpython.c -lpython2.7 -lm -L/usr/lib/python2.7/config && ./callpython helloworld helloworldFunc world
不打印“Hello world”,而是打印“Hello 0”
为什么它不将python函数参数解析为字符串?
答案 0 :(得分:2)
示例代码将参数解析为整数,您已经传递了一个字符串。 atoi("world")
返回0,所以这是你得到的整数:
/* Create tuple of the correct length for the arguments. */
pArgs = PyTuple_New(argc - 3);
for (i = 0; i < argc - 3; ++i) {
/* Convert each C argv to a C integer, then to a Python integer. */
pValue = PyInt_FromLong(atoi(argv[i + 3]));
if (!pValue) {
Py_DECREF(pArgs);
Py_DECREF(pModule);
fprintf(stderr, "Cannot convert argument\n");
return 1;
}
/* iValue reference stolen here: */
/* Store the Python integer in the tuple at the correct offset (i) */
PyTuple_SetItem(pArgs, i, pValue);
}
将转换行更改为以下内容以处理任何字符串:
pValue = PyString_FromString(argv[i + 3]);
答案 1 :(得分:0)
解决了这个问题。罪魁祸首就是这条线
pValue = PyInt_FromLong(atoi(argv[i + 3]));
它将python脚本的每个参数解析为整数。
当替换为以下行时,它将每个参数解析为字符串
pValue = PyString_FromString(argv[i+3]);
我还没有真正了解pValue是如何工作的,但现在解决了这个问题。