Question

我有一组用户名（ids），我需要使用Firebase数据库进行搜索并使用Firebase UI进行渲染，我这样做的方式只显示最后一个用户而不是所有拥有这些ID的用户。我需要使用不同的ID呈现卡片或所有用户。

这是我的班级

public class UserMessageListFragment extends Fragment {

    private ProgressDialog progressDialog;
    private final String TAG = "UsersMessageList";
    private RecyclerView mResultList;
    private ArrayList<String> arrayUsers;

    public static UserMessageListFragment newInstance() {
        return new UserMessageListFragment();
    }

    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
                             Bundle savedInstanceState) {
        View view = inflater.inflate(R.layout.fragment_user_message_list, container, false);

        mResultList = view.findViewById(R.id.message_list);
        mResultList.setHasFixedSize(true);
        mResultList.setLayoutManager(new LinearLayoutManager(mResultList.getContext()));

        final DatabaseReference refMessages = FirebaseDatabase.getInstance().getReference();
        final DatabaseReference ref= FirebaseDatabase.getInstance().getReference().child("usuarios");

        refMessages.addChildEventListener(new ChildEventListener() {
            @Override
            public void onChildAdded(DataSnapshot dataSnapshot, String s) {
                if(dataSnapshot.getKey().contains(UserDetails.username+ "_")) {
                    String[] userChatWithId = dataSnapshot.getKey().split(UserDetails.username+"_");
                    final Query firebaseSearchQuery = ref.orderByChild("username").equalTo(userChatWithId[1]);
                    final FirebaseRecyclerOptions<User> options =
                            new FirebaseRecyclerOptions.Builder<User>()
                                    .setQuery(firebaseSearchQuery, User.class)
                                    .build();
                    bindAndBuildFirebaseUi(options);
                }
            }

            @Override
            public void onChildChanged(DataSnapshot dataSnapshot, String s) {

            }

            @Override
            public void onChildRemoved(DataSnapshot dataSnapshot) {

            }

            @Override
            public void onChildMoved(DataSnapshot dataSnapshot, String s) {

            }

            @Override
            public void onCancelled(DatabaseError databaseError) {

            }
        });
//        progressDialog = new ProgressDialog(getContext());
//        progressDialog.setMessage("Carregando...");
//        progressDialog.show();

        return view;
    }


    public void bindAndBuildFirebaseUi(FirebaseRecyclerOptions options) {
        final FirebaseRecyclerAdapter<User, UsersViewHolder> firebaseRecyclerAdapter = new FirebaseRecyclerAdapter<User, UsersViewHolder>(options) {
            @Override
            public UsersViewHolder onCreateViewHolder(ViewGroup parent, int viewType) {
                View v = LayoutInflater.from(parent.getContext()).inflate(R.layout.message_list_layout, parent, false);
                return new UsersViewHolder(v);
            }

            @Override
            protected void onBindViewHolder(final UsersViewHolder holder, int position, final User model) {
                holder.bind(model);
                holder.itemView.setOnClickListener(new View.OnClickListener() {
                    @Override
                    public void onClick(View v) {
                        UserDetails.chatWithId = model.getUsername();
                        UserDetails.chatWith = model.getName();
                        startActivity(new Intent(getContext(), Chat.class));
                    }
                });
            }
        };
        firebaseRecyclerAdapter.startListening();
        mResultList.setAdapter(firebaseRecyclerAdapter);
    }
}

在这一行

 final Query firebaseSearchQuery = ref.orderByChild("username").equalTo(userChatWithId[1]);

userChatWithid 1中会有不同的值，但FirebaseUI只渲染最后一个。

我开始讨厌FirebaseUI，因为我一直有这么多问题。

有人可以帮助我吗？

Answer 1

您正在做一些非常规的事情...... FirebaseUI将为您处理所有数据库侦听器和查询。您应该做的只是传递包含所有用户的根节点，其余的将被处理。（我相信你的情况是usuarios所以ref可以解决问题。）我建议你阅读文档：https://github.com/firebase/FirebaseUI-Android/blob/master/database/README.md

FirebaseUI不允许我使用Firebase数据库搜索多个

1 个答案: