SQL Server：给定一年找到前一年和给定年份的所有内容（包括）

Question

我不熟悉SQL Server语法，但我想它会是这样的：

$year = 2010;

$query = mssql_query("SELECT * FROM dbo.events 
                      WHERE date BETWEEN $year AND $year-1");

在这种情况下，我只是不确定如何格式化$ year。

Answer 1

你很亲密。假设date列是datetime数据类型：

SELECT *
    FROM dbo.events
    WHERE DATEPART(year, date) BETWEEN $year-1 AND $year

Answer 2

SQL Server有YEAR function，写入比DATEPART更短：

select * from dbo.events where year(date) between $year-1 and $year

Answer 3

你试图只选择一年吗？

这对我有用：

$year = 2011;
select * from table where year(date_field) = $year

Answer 4

试试这个：

declare @year int
set @year=2010

select * from FROM dbo.events 
WHERE cast(YEAR([date]) as int) <= @year 
and cast(YEAR([date]) as int) >= @year-1