简单的SQL记录删除 - 不起作用

Question

所有我想做的就是有一个简单的文本形式从sql数据库中删除记录 它返回记录被删除但它实际上从未删除记录。

variablesremove.php：

html表单图片：

remove.php：

remove.php：

require('variablesremove.php');

$user = "#"; 
$password = "#"; 
$host = "localhost"; 
$database= "#";

$connection= mysqli_connect ($host, $user, $password);
if (!$connection) {
    die ('Could not connect:' . mysql_error());
}

mysqli_select_db($database, $connection);

$deleterow = "DELETE FROM licenses WHERE serialNumber='$serialNumber'";

if($deleterow !== FALSE) {
    echo("The row has been deleted.");
} else {
    echo("The row has not been deleted.");
}

Answer 1

您需要使用mysqli_query()执行删除命令。

$deleteRow = "DELETE FROM licenses WHERE serialNumber='$id'";

if (mysqli_query($connection, $deleteRow)) {
  echo "Record deleted successfully";
} else {
  echo "Error deleting record: " . mysqli_error($conn);
}

mysqli_close($conn);

Answer 2

...
mysqli_select_db($database, $connection);

$deleterow = "DELETE FROM licenses WHERE serialNumber = '$serialNumber'";

if(mysqli_query($conn, $deleterow)) {
    echo("The row has been deleted.");
} else {
    echo("The row has not been deleted.");
}
...

Answer 3

您可以将此作为示例 -

<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";

// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}

// sql to delete a record
$sql = "DELETE FROM MyGuests WHERE id=3";

if (mysqli_query($conn, $sql)) {
    echo "Record deleted successfully";
} else {
    echo "Error deleting record: " . mysqli_error($conn);
}

mysqli_close($conn);
?>

Answer 4

您实际应该使用参数化查询来运行此语句。

在它的现有形式中，它受到SQL注入攻击。

if($deleterow = $mysqli->prepare("DELETE FROM licenses WHERE serialNumber = ?") {
    $deleterow->bind_param("s", $id);
    if ($deleterow->execute()) {
        printf("The row has been deleted.\n");
    }else{
        echo "Error deleting record: " . mysqli_error($conn);
    }
} else {
    printf("Error preparing the query: %s\n",$deleterow);
}

$mysqli->close();

Answer 5

感谢所有人的帮助！

这是工作解决方案！

<?php
require('variablesremove.php');
$user = "#"; 
$password = "#"; 
$host = "#"; 
$database = "#";

$connection= mysqli_connect ($host, $user, $password);

if (!$connection)

{

die ('Could not connect:' . mysql_error());

}

mysqli_select_db($connection, "$database") or die ("Couldn't select the database."); 

$deleteRow = "DELETE FROM licenses WHERE serialNumber='$id'";

if (mysqli_query($connection, $deleteRow)) {
  echo "Record deleted successfully";
} else {
  echo "Error deleting record: " . mysqli_error($connection);
}

mysqli_close($connection);
?>