我正在开发一个用于求职的Android应用程序，这里PHP作为后端。从服务器获取作业列表并显示为卡片视图运行良好。我想要搜索位置和职位。所以如何将我的位置和职位从搜索活动传递到工作活动。
private void searchjob() {
final String title = jobtitle.getText().toString().trim();
final String location = city.getSelectedItem().toString().trim();
Intent intent = new Intent(HomeActivity.this, MainActivity.class);
intent.putExtra(title,1);
intent.putExtra(location,2);
startActivity(intent);
overridePendingTransition(R.anim.slide_in, R.anim.slide_out);
}
这是我的下载卡java类。
public class DownloaderCard extends AsyncTask<Void, Integer, String> {
Context c;
String address;
SwipeDeck swipeDeck;
ProgressDialog pd;
String url = "";
public DownloaderCard(Context c, String address, SwipeDeck swipeDeck) {
this.c = c;
this.address = address;
this.swipeDeck = swipeDeck;
}
@Override
protected void onPreExecute() {
super.onPreExecute();
pd = new ProgressDialog(c);
pd.setTitle("Please Wait");
pd.setMessage("Loading....");
pd.show();
}
@Override
protected String doInBackground(Void... params) {
String data = downloadData();
return data;
}
@Override
protected void onPostExecute(String s) {
super.onPostExecute(s);
pd.dismiss();
if(s!=null){
//Toast.makeText(c, s, Toast.LENGTH_LONG).show();
ParserCard p = new ParserCard(c, s, swipeDeck);
p.execute();
}else {
Toast.makeText(c, "Unable to download data from downloader", Toast.LENGTH_LONG).show();
}
}
private String downloadData(){
InputStream is = null;
String line = null;
try {
URL url = new URL(address);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
is = new BufferedInputStream(connection.getInputStream());
BufferedReader br = new BufferedReader(new InputStreamReader(is));
StringBuffer sb = new StringBuffer();
if(br != null){
while ((line = br.readLine()) != null){
sb.append(line+"\n");
}
}else {
return null;
}
return sb.toString();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} finally {
if(is != null){
try {
is.close();
}catch (IOException e){
e.printStackTrace();
}
}
}
return null;
}
}
这是我的JobActivity。
String urlData = "https://www.joblist.php";
final DownloaderCard dl = new DownloaderCard(MainActivity.this,urlData , cardStack);
dl.execute();
cardStack.setEventCallback(new SwipeDeck.SwipeEventCallback() {
@Override
public void cardSwipedLeft(int position) {
// Log.i("MainActivity", "card was swiped left, position in adapter: " + position);
}
@Override
public void cardSwipedRight(int position) {
// Log.i("MainActivity", "card was swiped right, position in adapter: " + position);
}
@Override
public void cardsDepleted() {
// Log.i("MainActivity", "no more cards");
}
@Override
public void cardActionDown() {
// Log.i(TAG, "cardActionDown");
}
@Override
public void cardActionUp() {
// Log.i, "cardActionUp");
}
});
cardStack.setLeftImage(R.id.left_image);
cardStack.setRightImage(R.id.right_image);
btn.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
cardStack.swipeTopCardLeft(180);
}
});
btn2.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
cardStack.swipeTopCardRight(180);
}
});
}
答案 0 :(得分：1)
这是我用来向PHP服务器发送登录信息的方法。更新它以便它符合您的目的。
public String LoginOnService(String url,String email,String pass){
InputStream inputStream = null;
String result = "";
try {
// 1. create HttpClient
HttpClient httpclient = new DefaultHttpClient();
// 2. make POST request to the given URL
HttpPost httpPost = new HttpPost(url+"?email="+email+"&password="+pass);
// 3. Execute POST request to the given URL
HttpResponse httpResponse = httpclient.execute(httpPost);
if(httpResponse != null){
result = EntityUtils.toString(httpResponse.getEntity());
}else{
result = "Did not work!";
}
} catch (Exception e) {
Log.d("InputStream", e.getLocalizedMessage());
}
// 11. return result
return result;
}
正如您所看到的，我正在传递String，但如果您想将数据发送为JSON，您也可能会从这些评论中受益。但在第2步中只传递了一个网址HttpPost httpPost = new HttpPost(url);
public String LoginOnService(String url,String email,String pass){
InputStream inputStream = null;
String result = "";
try {
// 1. create HttpClient
HttpClient httpclient = new DefaultHttpClient();
// 2. make POST request to the given URL
HttpPost httpPost = new HttpPost(url+"?email="+email+"&password="+pass);
// String json = YOUR_JSON_STRING;
// 3. build jsonObject
// JSONObject jsonObject = new JSONObject();
// jsonObject.accumulate("Email", user.getEmail());
// jsonObject.accumulate("Password", user.getPassword());
// 4. convert JSONObject to JSON to String
// json = jsonObject.toString();
// ** Alternative way to convert Person object to JSON string usin Jackson Lib
// ObjectMapper mapper = new ObjectMapper();
// json = mapper.writeValueAsString(person);
// 5. set json to StringEntity
// StringEntity se = new StringEntity(json);
// 6. set httpPost Entity
// httpPost.setEntity(se);
// 7. Set some headers to inform server about the type of the content
// httpPost.setHeader("Accept", "application/json");
// httpPost.setHeader("Content-type", "application/json");
// 8. Execute POST request to the given URL
HttpResponse httpResponse = httpclient.execute(httpPost);
// 9. receive response as inputStream
// inputStream = httpResponse.getEntity().getContent();
// 10. convert inputstream to string
if(httpResponse != null)
result = EntityUtils.toString(httpResponse.getEntity());
else
result = "Did not work!";
} catch (Exception e) {
Log.d("InputStream", e.getLocalizedMessage());
}
// 11. return result
return result;
}
答案 1 :(得分：1)
您应该使用Volley https://github.com/google/volley来拨打 Http Requests ，这会让您的工作更轻松，
这是一个例子： -
final String url = "https://www.joblist.php?title=MyJobTitle&location=London";
// prepare the Request
JsonObjectRequest getRequest = new JsonObjectRequest(Request.Method.GET, url, null,
new Response.Listener<JSONObject>()
{
@Override
public void onResponse(JSONObject response) {
// display response
Log.d("Response", response.toString());
}
},
new Response.ErrorListener()
{
@Override
public void onErrorResponse(VolleyError error) {
Log.d("Error.Response", response);
}
}
);
// add it to the RequestQueue
queue.add(getRequest);
答案 2 :(得分：0)
final String title = jobtitle.getText().toString().trim();
final String location = city.getSelectedItem().toString().trim();
Intent intent = new Intent(HomeActivity.this, MainActivity.class);
intent.putExtra("job_title",title);
intent.putExtra("city",location);
String myvalue= getIntent().getExtras("job_title");
String myvalue2= getIntent().getExtras("city");
php code
final String url =＆＃34; https://www.joblist.php?title=＆＃34; + myvalue +＆＃34;＆amp; location =＆＃34; + myvalue2;