我有以下ajax请求,它返回一个json对象(我认为)。当我读取console.log(response);
的结果时,你可以看到cartcount的值我想将var bill设置为等于cartcount的值,在下面的示例中等于“1”。我尝试了很多方法,但我怀疑我对json有误解。
$.ajax({
url: app_config.ajax_cart_add,
type: 'POST',
data: data,
dataType: "json",
beforeSend: function() {
},
success: function(response) {
if (response.success === true) {
console.log(response);
var bill = $(response.cartcount);
console.log(bill);
App.success('Item was successful.');
}
if (response.success === false) {
App.error('There was a proble');
}
}
});
我的控制台日志为console.log打印(响应);
{success: true, cartcount: "1"}
cartcount:"1"
success:true
proto:Object
a bunch of stuff in the proto object that seems irrelevant to my question.
答案 0 :(得分:3)
不要将数据包装在$()
中。它正在创建一个不必要的jQuery对象
更改
var bill = $(response.cartcount);
要
var bill = response.cartcount;