我听说int 10h,啊= 0Ch非常慢,为了获得合理的速度,我需要转到内存并将值放入我想要的像素中,我将视频模式设置为{{ 1}}与13h
。
改变视频模式的呼吁:
int 10h
这是我为了将像素放在给定坐标中而编写的程序:
mov ah , 0
mov al , 13h
int 10h
调用函数的代码:
drawFaster proc
; bp + 2 - row (dx)
; bp + 4 - column (cx)
; bp + 6 - color
mov bp , sp
pushad
mov ax , 0A000h - presumably the memory address of the screen
mov es , ax
mov ax , [bp + 2]
mov bx , [bp + 4]
mov cx , 320
mul cx
add ax , bx
mov di , ax
mov ax , [bp + 6]
mov [es:di] , al
popad
ret 6
endp
但由于某种原因,这没有结果,我不知道内存地址是否不正确或是否有其他内容。我需要你的帮助。谢谢!
奇怪的是,下面的代码工作
push bp
mov ax , 30
push ax
mov cx , 50
push cx
mov dx , 50
push dx
call drawFaster
pop bp
但下面的代码不是:
mov ax , 0A000H
mov es , ax
mov [es:0] , 30
答案 0 :(得分:0)
我找到了一种解决方法,但它可能不是最好的方法,而不是使用es
(因为它不起作用)
我将数据段的地址更改为0A000H
,
然后我用mov [di] , al
更改像素,它可以正常工作!
但是如果你这样做,请务必将数据段的地址移回原来的位置。
我的功能处于工作状态,如果有人感兴趣的话:
drawFaster proc
; bp + 2 - row (dx)
; bp + 4 - column (cx)
; bp + 6 - color
mov bp , sp ; changing bp to access the stack segment
; pushing the values to not lose them in the process of calling the function
push ax
push bx
push cx
push dx
mov ax, 0A000h ; 0A000h is the video memory address (for some video modes like 13h)
mov ds , ax
mov ax , [bp + 2] ; getting the row ( Y )
mov bx , [bp + 4] ; getting the column ( X )
mov cx , 320 ; multiplying the row by 320 to get the offset, and then adding the column
mul cx
add ax , bx
mov di , ax
mov ax , [bp + 6] ; getting the desired color to paint the pixel in
mov [di] , al ; changing the color of the chosen pixel with the desired color
; changing the data segment's address back to its original state
; VERY CRUCIAL PLEASE DON'T MISS THIS IF YOU DO IT THE SAME WAY
mov ax , @data
mov ds, ax
; changing the values back to what they were
pop dx
pop cx
pop bx
pop ax
ret 6
endp