Question

我的MYSQL查询中有一个小的语法问题我似乎无法修复，看起来相当简单，这里是查询：

$dates = DB::getInstance()->select("             
    SELECT today.clicks AS clicksToday, today.spend_amount AS amountToday, 
       yesterday.clicks AS clicksYesterday, yesterday.spend_amount AS amountYesterday,
       week.clicks AS clicksWeekly, week.spend_amount AS amountWeekly,
       month.clicks AS clicksMonthly, month.spend_amount AS amountMonthly
    FROM
           (SELECT COUNT(*) clicks, SUM(spend_amount) spend_amount
              FROM spending
             WHERE spend_date >= CURDATE()) today
    JOIN           
           (SELECT COUNT(*) clicks, SUM(spend_amount) spend_amount
              FROM spending
             WHERE spend_date >= CURDATE() - INTERVAL 1 DAY
               AND spend_date < CURDATE()) yesterday
    JOIN
           (SELECT COUNT(*) clicks, SUM(spend_amount) spend_amount
              FROM spending
             WHERE spend_date >= CURDATE() - INTERVAL 7 DAY
               AND spend_date < CURDATE()) week
    JOIN        
           (SELECT COUNT(*) clicks, SUM(spend_amount) spend_amount
              FROM spending
             WHERE spend_date >= LAST_DAY(CURDATE()) + INTERVAL 1 DAY - INTERVAL 1 MONTH) month

    JOIN   WHERE spend_user_id='{$globId}'";

问题在于这一部分： JOIN WHERE spend_user_id ='{$ globId}''; $ globId包含用户唯一ID，如果我走这条线它可以正常工作但是拉出所有数据，我真的需要它使用ID，我不能确切地看到我做错了什么，任何帮助将不胜感激。

SQLFiddle： http://sqlfiddle.com/#!9/c3c694/1

Answer 1

我会将spend_user_id过滤器合并到子查询中：

$dates = DB::getInstance()->select("             
    SELECT today.clicks AS clicksToday, today.spend_amount AS amountToday, 
       yesterday.clicks AS clicksYesterday, yesterday.spend_amount AS amountYesterday,
       week.clicks AS clicksWeekly, week.spend_amount AS amountWeekly,
       month.clicks AS clicksMonthly, month.spend_amount AS amountMonthly
    FROM
           (SELECT COUNT(*) clicks, SUM(spend_amount) spend_amount
              FROM spending
             WHERE spend_date >= CURDATE() AND spend_user_id='{$globId}') today
    JOIN           
           (SELECT COUNT(*) clicks, SUM(spend_amount) spend_amount
              FROM spending
             WHERE spend_date >= CURDATE() - INTERVAL 1 DAY
               AND spend_date < CURDATE() AND  spend_user_id='{$globId}') yesterday
    JOIN
           (SELECT COUNT(*) clicks, SUM(spend_amount) spend_amount
              FROM spending
             WHERE spend_date >= CURDATE() - INTERVAL 7 DAY
               AND spend_date < CURDATE() AND  spend_user_id='{$globId}') week
    JOIN        
           (SELECT COUNT(*) clicks, SUM(spend_amount) spend_amount
              FROM spending
             WHERE spend_date >= LAST_DAY(CURDATE()) + INTERVAL 1 DAY - INTERVAL 1 MONTH AND  spend_user_id='{$globId}') month";

添加了WHERE子句的MYSQL语法

1 个答案: