Question

我设法通过下面的构造函数将Stateful类变量值传递给State类：

import 'package:flutter/material.dart';

void main() => runApp(MyApp());

class MyApp extends StatelessWidget {
  @override
  Widget build(BuildContext context) {
    return MaterialApp(
        title: 'Demo',
        home: MyHomePage('John', 'Morison'),
    );
  }
}

class MyHomePage extends StatefulWidget {
  MyHomePage(this.fname, this.lname);

  final String fname;
  final String lname;

  @override
  _MyHomePageState createState() => _MyHomePageState(fname, lname);
}

class _MyHomePageState extends State<MyHomePage> {
  _MyHomePageState(this.fname, this.lname);

  final String fname;
  final String lname;

  @override
  Widget build(BuildContext context) {
    return Scaffold(
      body: Center(
        child: Text('Hello $fname $lname'),
      )
    );
  }
}

当我有两个以上的变量时，这很奇怪并且必须做很多工作。还有比这更好的方法吗？

Answer 1

是的，有widget：

来自Doc：

  /// The current configuration.
  ///
  /// A [State] object's configuration is the corresponding [StatefulWidget]
  /// instance. This property is initialized by the framework before calling
  /// [initState]. If the parent updates this location in the tree to a new
  /// widget with the same [runtimeType] and [Widget.key] as the current
  /// configuration, the framework will update this property to refer to the new
  /// widget and then call [didUpdateWidget], passing the old configuration as
  /// an argument.
  T get widget => _widget;
  T _widget;

代码应如下所示：

import 'package:flutter/material.dart';

void main() => runApp(MyApp());

class MyApp extends StatelessWidget {
  @override
  Widget build(BuildContext context) {
    return MaterialApp(
        title: 'Demo',
        home: MyHomePage('John', 'Morison'),
    );
  }
}

class MyHomePage extends StatefulWidget {
  MyHomePage(this.fname, this.lname);

  final String fname;
  final String lname;

  @override
  _MyHomePageState createState() => _MyHomePageState();
}

class _MyHomePageState extends State<MyHomePage> {

  @override
  Widget build(BuildContext context) {
    return Scaffold(
      body: Center(
        child: Text('Hello ${widget.fname} ${widget.lname}'),
      )
    );
  }
}

不使用构造函数将StatefultWidget数据传递给State类

1 个答案: