Question

每当我运行此代码并告诉启动函数“google”时，它会返回另一个函数。我已经试着这几天了，但仍然没有运气。任何帮助将不胜感激:)）

import webbrowser
import string
import time
import pyttsx3
import speech_recognition as sr
engine = pyttsx3.init()
r = sr.Recognizer()

def Listen():
    with sr.Microphone() as sourceL:
        print("Listening...")
        Open = r.listen(sourceL, phrase_time_limit=2)
    try:
        if "Nova" in r.recognize_google(Open):
            print("Nova Recieved...")
            Command()
        else:
            Listen()
    except:
        Listen()

def Google():
    print("what would you like me to search for you? ")
    engine.say("what would you like me to search for you? ")
    engine.runAndWait()
    with sr.Microphone as source:
        Search = r.listen(source)
        Search = r.recognize(Search)

代码将返回with sr.Mirophone as source的Listen（）这就是我调用google（）的方式......

def Command():
    print("You called me?")
    engine.say("you called me? ")
    engine.runAndWait()
    Cr = sr.Recognizer()
    with sr.Microphone() as source:
        print("Listening For Command...")
        CommandToDo = Cr.listen(source, phrase_time_limit=2)
        print("...")
    if "YouTube" in Cr.recognize_google(CommandToDo):
        YouTube()

    elif "Google" in Cr.recognize_google(CommandToDo):
        Google()

    else:
        print("Command not recognized>> " + r.recognize_google(CommandToDo))

Answer 1

在phrase_time_limit函数内调用listen方法时，需要指定一个函数参数Google。
phrase_time_limit表示程序的等待时间，等待用户提供输入的秒数。在这里等待2秒钟。如果您没有给出任何时间限制，它将无限期地等待。

从源代码文档：

phrase_time_limit参数是最大秒数这将允许一个短语在停止之前继续返回在时间限制之前处理的短语部分到达。结果音频将是当时截止的短语限制。如果phrase_timeout为None，则不会有短语时间限制。

澄清timeout参数

timeout参数是此参数的最大秒数在放弃投掷之前会等待一个短语开始 speech_recognition.WaitTimeoutError例外。如果是timeout None，没有等待超时。

有关详细信息，请查看the source code.

def Google():
    print("what would you like me to search for you? ")
    engine.say("what would you like me to search for you? ")
    engine.runAndWait()
    with sr.Microphone() as source:
        Search = r.listen(source, phrase_time_limit=2)  # <-- Here
        Search = r.recognize_google(Search)
        print(Search)

这次改变之后，它对我有用检查是否是 with sr.Microphone() as source:没有 with sr.Microphone as source:。你错过了大括号。

我转到另一个功能后，我的麦克风又回去听了

1 个答案: