Question

$('.remove_proposal_file').unbind('click').bind('click', function(){

            var file_row_id = $(this).attr('fileid');
            var obj = $(this);

            $.ajax({
                url : '<?=base_url();?>project/remove_proposal_file',
                method: 'POST',
                data: {
                   frow_id: file_row_id,
                   action: 'remove_file_supplier',
                  '<?=$csrf['name'];?>': '<?=$csrf['hash'];?>'
                },
                success: function( data ) {
                    var arr = $.parseJSON(data);    

                    if(arr['status'] == 1   ){
                        $(obj).parent().remove();
                        $('.file_remove_msg').show();
                        setTimeout(function(){ $('.file_remove_msg').hide(); }, 7000);
                    }

                    click_handler();
                }
            }); 

        });

以上代码是为删除单个文件而编写的。我想删除多个文件，以便如何删除？

Answer 1

我认为您在询问如何从浏览器发出多个AJAX请求以逐个删除文件。但是，这是错误的做法。

目前，您正在通过import java.io.BufferedReader; import java.io.File; import java.io.InputStreamReader; import java.util.ArrayList; public class ShellFromJava { public static ArrayList<String> command(final String cmdline, final String directory) { try { Process process = new ProcessBuilder(new String[] {"bash", "-c", cmdline}) .redirectErrorStream(true) .directory(new File(directory)) .start(); ArrayList<String> output = new ArrayList<String>(); BufferedReader br = new BufferedReader(new InputStreamReader(process.getInputStream())); String line = null; while ( (line = br.readLine()) != null ) output.add(line); if (0 != process.waitFor()) return null; return output; } catch (Exception e) { //Warning: doing this is no good in high-quality applications. //Instead, present appropriate error messages to the user. //But it's perfectly fine for prototyping. return null; } } public static void main(String[] args) { testHandler("curl http://stackoverflow.com"); } static void testHandler(String cmdline) { ArrayList<String> output = command(cmdline, "."); if (null == output) System.out.println("\n\n\t\tCOMMAND FAILED: " + cmdline); else for (String line : output) System.out.println(line); } }单独删除文件：

post

如何使用Ajax删除多个文件？

1 个答案: