PHP分页脚本没有显示页码的正确内容

时间:2018-05-19 10:57:45

标签: php pagination ceil

我已经构建了一个php脚本来反复导航我的博客页面,但是第一页显示正确,但是当我导航到下一页时它会显示正确的数字,但仍然显示相同的内容之前。然后,下一个按钮会一直显示当前页面。

这是我的剧本:

$publication = "magazine";
$ppp = "6";

if(isset($_GET["id"])){$id = $_GET["id"];}else{
header("Location: ".$url."");
exit();
}

if(isset($_GET["currentpage"])){$currentpage = $_GET["currentpage"];}else{
header("Location: ".$url."");
exit();
}

$count_sql = "SELECT id FROM publication_posts WHERE publication = '".$publication."' AND issue = '".$id."'";
$count_res = mysqli_query($con, $count_sql);
$count_total = mysqli_num_rows($count_res);
//If None, Then Exit
if($count_total == 0){
header("Location: ".$url."");
exit();
}

$display_limit = $ppp;
$totalpages = ceil($count_total / $display_limit);//$rowsperpage
$currentpage = $totalpages;

$offset = ($totalpages - 1) * $display_limit;//$rowsperpage

if($currentpage == "0"){
header("Location: ".$url."/issue/".$id."/".$totalpages."");
exit();
}

$posts_sql = "SELECT * FROM publication_posts WHERE publication = '".$publication."' AND issue = '".$id."' ORDER BY id DESC LIMIT ".$offset.", ".$display_limit."";

我在此注意到的另一件事是,如果我将当前页面设置为0,它仍会显示issue/id/0,而这应该重定向到$totalpages

任何人都知道问题在哪里?

这是我的分页:

<?php
// range of num links to show
$range = 0;
if ($currentpage != $totalpages) {
    // get next page
    $nextpage = $currentpage + 1;
    // echo forward link for next page
    $link_next = "<a href=\"issue/".$id."/".$nextpage."\"><div class=\"pagiCell pagiNext fadeOut\"></div></a>";
}
else{
    $link_next = "<div class=\"pagiCell pagiNextX\"></div>";
}
?>
<?php
// range of num links to show
$range = 0;
if ($currentpage > 1) {
    // get previous page
    $prevpage = $currentpage - 1;
    // echo forward link for next page
    $link_prev = "<a href=\"issue/".$id."/".$prevpage."\"><div class=\"pagiCell pagiPrev fadeOut\"></div></a>";
}
else{
    $link_prev = "<div class=\"pagiCell pagiPrevX\"></div>";
}
?>
<?php
    $link_refresh = "<a href=\"issue/".$id."/1\"><div class=\"pagiCell pagiRefresh fadeOut\"></div></a>";
?>
<?php
    $randpage = rand(1,$totalpages);
    $link_random = "<a href=\"issue/".$id."/".$randpage."\"><div class=\"pagiCell pagiRandom fadeOut\"></div></a>";
?>

短网址:localhost/publication/magazine/issue/1/1 长网址:localhost/publication/magazine/issue?id=1&currentpage=1

1 个答案:

答案 0 :(得分:0)

我认为您的问题是您的$currentpage var是一个字符串,而您正在使用它进行数学运算而不进行转换。你应该输入cast it:PHP: Type Juggling

$nextpage = $currentpage + 1; 变为$nextpage = (int)$currentpage + 1;

就像Magnus Eriksson之前所说的那样,您没有检查用户输入是否存在安全问题。测试变量的预期值意味着,例如PHP: is_int