Question

型号：

$this->db->where('payment_details.created_on >= ',$start_date);
    $this->db->where('payment_details.created_on <= ',$end_date);
    $this->db->where('receipt_details.created_on >= ',$start_date);
    $this->db->where('receipt_details.created_on <= ',$end_date);        
    $this->db->select('payment_details.id,payment_details.payment_no,payment_details.site_id,payment_details.vendor_id,payment_details.work,payment_details.description,payment_details.date,payment_details.amount,payment_details.tax_type,payment_details.tax,payment_details.subtotal,payment_details.grand_total,payment_details.created_on,receipt_details.id,receipt_details.receipt_no,receipt_details.site_id,receipt_details.vendor_id,receipt_details.work,receipt_details.description,receipt_details.date,receipt_details.amount,receipt_details.tax_type,receipt_details.tax,receipt_details.subtotal,receipt_details.grand_total,receipt_details.created_on,vendor.id,vendor.vname,site.id,site.sname');

$this->db->from('payment_details');        
$this->db->join('vendor','vendor.id=payment_details.vendor_id OR vendor.id=receipt_details.vendor_id','LEFT');
$this->db->join('site','site.id=payment_details.site_id OR site.id=receipt_details.site_id','LEFT');
return $this->db->get()->result();

enter image description here

我会尝试但运行此查询时出错错误：错误号码：1064

您的SQL语法有错误;检查与您的MariaDB服务器版本对应的手册，以便在{LEFT JOIN vendor ON vendor附近使用正确的语法。id = payment_details。vendor_id或者vendor。“我在第2行

选择payment_details。id，payment_details。payment_no，payment_details。site_id，payment_details。{{1} }，vendor_id。payment_details，work。payment_details，description。payment_details，date。payment_details， amount。payment_details，tax_type。payment_details，tax。payment_details，subtotal。payment_details，{{ 1}}。grand_total，payment_details。created_on，receipt_details。id，receipt_details。receipt_no，{{1} }。receipt_details，site_id。receipt_details，vendor_id。receipt_details，work。receipt_details，description。 receipt_details，date。receipt_details，amount。receipt_details，tax_type。receipt_details，tax。{{ 1}}，receipt_details。subtotal，receipt_details。grand_total，receipt_details。created_on，vendor。{{1} }，id。vendor LEFT JOIN vname ON site。id = site。sname或vendor 。vendor = id。payment_details LEFT JOIN vendor_id ON vendor。id = receipt_details。vendor_id或site。site = id。payment_details WHERE site_id。site＆gt; ='2018-05-01'和{{1} }。id＆lt; ='2018-05-31'和receipt_details。site_id＆gt; ='2018-05-01'和payment_details。{{1} }＆lt; ='2018-05-31'

文件名：D：/xampp/htdocs/construct/system/database/DB_driver.php

行号：691 提前谢谢......

Answer 1

希望这会对您有所帮助：（未经测试）

您的查询结构应该是这样的，只需提示您做必要的更改

$sql = 'SELECT payment_details.id,payment_details.payment_no,payment_details.site_id,payment_details.vendor_id,payment_details.work,payment_details.description,payment_details.date,payment_details.amount,payment_details.tax_type,payment_details.tax,payment_details.subtotal,payment_details.grand_total,payment_details.created_on,receipt_details.id,receipt_details.receipt_no,receipt_details.site_id,receipt_details.vendor_id,receipt_details.work,receipt_details.description,receipt_details.date,receipt_details.amount,receipt_details.tax_type,receipt_details.tax,receipt_details.subtotal,receipt_details.grand_total,receipt_details.created_on,vendor.id,vendor.vname,site.id,site.sname 
        FROM payment_details  
        JOIN (vendor, receipt_details, site)
        ON (vendor.id=payment_details.vendor_id OR vendor.id=receipt_details.vendor_id
        AND site.id=payment_details.site_id OR site.id=receipt_details.site_id)';
$query = $this->db->query($sql);
return $query->result();

使用codeigniter和mysql

1 个答案: