Question

我试图从下面给出的JSON中获取“photo_reference”中的字符串。但是，我得到了一个不匹配的例外。但我认为我做得对.Mismatch例外是结果，但可以清楚地看到结果是对象数组

{
   "html_attributions" : [],
   "results" : [
      {


         "name" : "Rhythmboat Cruises",

         "photos" : [
            {
               ,
               "photo_reference" : "CnRnAAAAF-LjFR1ZV93eawe1cU_3QNMCNmaGkowY7CnOf-kcNmPhNnPEG9W979jOuJJ1sGr75rhD5hqKzjD8vbMbSsRnq_Ni3ZIGfY6hKWmsOf3qHKJInkm4h55lzvLAXJVc-Rr4kI9O1tmIblblUpg2oqoq8RIQRMQJhFsTr5s9haxQ07EQHxoUO0ICubVFGYfJiMUPor1GnIWb5i8",
               "width" : 519
            }
         ],

      },
     ,
      {

         "name" : "Bucks Party Cruise",

         "photos" : [
            {

               "photo_reference" : "CnRnAAAA48AX5MsHIMiuipON_Lgh97hPiYDFkxx_vnaZQMOcvcQwYN92o33t5RwjRpOue5R47AjfMltntoz71hto40zqo7vFyxhDuuqhAChKGRQ5mdO5jv5CKWlzi182PICiOb37PiBtiFt7lSLe1SedoyrD-xIQD8xqSOaejWejYHCN4Ye2XBoUT3q2IXJQpMkmffJiBNftv8QSwF4",
               "width" : 800
            }
         ],

      },

以下是获取photo_reference的代码

 var arr: JSONArray = JSONArray(result)
                    var jsonObject:JSONObject=arr.getJSONObject(0)
                    var array:JSONArray=jsonObject.getJSONArray("photos")
                    var obj:JSONObject=array.getJSONObject(0)
                    var photoref:String=obj.getString("photo_reference")

Answer 1

您需要将根对象转换为JSONObject

  var rootObject :JSONObject = JSONObject(result);
  var arr: JSONArray = rootObject.getJSONArray("results")
  var jsonObject:JSONObject=arr.getJSONObject(0)
  var array:JSONArray=jsonObject.getJSONArray("photos")
  var obj:JSONObject=array.getJSONObject(0)
  var photoref:String=obj.getString("photo_reference")

可以搞清楚JSON不匹配

1 个答案: