Question

我想将一个wav文件转换为一个double数组来修改它的值，这是我的代码，但它不能正常工作：

    private void bytesToDouble(File file) throws IOException {
    ByteArrayOutputStream out = new ByteArrayOutputStream();
    BufferedInputStream in = new BufferedInputStream(new FileInputStream(file));

    int read;
    byte[] buff = new byte[1024];
    while ((read = in.read(buff)) > 0)
    {
        out.write(buff, 0, read);
    }
    out.flush();
    byte[] bytes = out.toByteArray();
    int times = Double.SIZE / Byte.SIZE;
    doubleArray = new double[bytes.length / times];
    for(int i=0;i<doubleArray.length;i++){
        doubleArray[i] = ByteBuffer.wrap(bytes, i*times, times).getDouble();
    }
}

这里我有一些示例输出：

bytes = {byte[148012]@4655} 
 0 = 82
 1 = 73
 2 = 70
 3 = 70
 4 = 36
 5 = 66
 6 = 2
 7 = 0
 8 = 87
 9 = 65
 10 = 86
 11 = 69
 12 = 102
 13 = 109
 14 = 116
 15 = 32
 16 = 16
 17 = 0
 18 = 0
 19 = 0
 20 = 1
 21 = 0
 22 = 2
 23 = 0
 24 = 68
 25 = -84
 26 = 0
 27 = 0
 28 = 16
 29 = -79
 30 = 2
 31 = 0
 32 = 4
 33 = 0
 34 = 16
 35 = 0
 36 = 100
 37 = 97
 38 = 116
 39 = 97
 40 = 0
 41 = 66
 42 = 2
 43 = 0
 44 = 0
 45 = 0
 46 = 0
 47 = 0
 48 = 0
 49 = 0
 50 = 0
 51 = 0
 52 = 0
 53 = 0
 54 = 0
 55 = 0
 56 = 0
 57 = 0
 58 = 0
 59 = 0
 60 = 0
 61 = 0
 62 = 0
 63 = 0
 64 = 0

其余字节也只是零。字节数组的大小约为150.000。输入是一个普通的音频wav文件。

这是我在修改双数组后将其转换回来的方式：

for (double aDoubleArray : doubleArray) {
        byteArray = ByteBuffer.allocate(8).putDouble(aDoubleArray).array();
    }

但要么它在第一次或第二次转换中都不起作用。谢谢你的帮助！

将wav文件转换为双数组

0 个答案: