Javascript字符串拆分和基于第一个字母组织

Question

我目前正在开发一个项目，我必须使用js和php从网关中检索数据。现在我已经检索了它，但数据没有组织：

{"timestamp":1526524809413,"data":[
{"_id":"rJeixnNtpG","data":"N11B00074","raw": 
[78,49,49,66,48,48,48,55,52],"timestamp":1525398515116}, 
{"_id":"HkzognEYpf","data":"N11E00000","raw": 
[78,49,49,69,48,48,48,48,48],"timestamp":1525398515479}, 
{"_id":"BJxXp4t6M","data":"N11A00029","raw": 
[78,49,49,65,48,48,48,50,57],"timestamp":1525398807747}

正如您所看到的，有三种类型的数据：一种是以B（N11B00074），E（N11E00000）和A（N11A00029）开头，后面是5位数，这是我想要从字符串中分割出来的数据按类型（B，E和A）分类。

我的网页上有三个表格，并希望根据类型将数据输入到它们中：如B是湿度表，A是温度表，E是pH读数表。

到目前为止，我只是设法将它们列在表格中。

有没有办法可以分离字符串并根据字符串将它们放入数组中？

Answer 1

您可以使用reduce对数组中的对象进行分组：

const input={"timestamp":1526524809413,"data":[{"_id":"rJeixnNtpG","data":"N11B00074","raw":[78,49,49,66,48,48,48,55,52],"timestamp":1525398515116},{"_id":"HkzognEYpf","data":"N11E00000","raw":[78,49,49,69,48,48,48,48,48],"timestamp":1525398515479},{"_id":"BJxXp4t6M","data":"N11A00029","raw":[78,49,49,65,48,48,48,50,57],"timestamp":1525398807747}]}
const arranged = input.data.reduce((accum, obj) => {
  const { data } = obj;
  const type = data[3];
  const digits = data.slice(5);
  if (!accum[type]) accum[type] = [];
  accum[type].push({ ...obj, digits });
  return accum;
}, {});
console.log(arranged);

// If you want an array and not an object:
console.log(Object.values(arranged));

Answer 2

如果要将数组分组到对象中。您可以使用reduce。您可以使用charAt

获取字符串的第四个字符

＆＃13;

＆＃13;

let arr = {"timestamp":1526524809413,"data":[{"_id":"rJeixnNtpG","data":"N11B00074","raw": [78,49,49,66,48,48,48,55,52],"timestamp":1525398515116}, {"_id":"HkzognEYpf","data":"N11E00000","raw": [78,49,49,69,48,48,48,48,48],"timestamp":1525398515479}, {"_id":"BJxXp4t6M","data":"N11A00029","raw":[78,49,49,65,48,48,48,50,57],"timestamp":1525398807747}]};

let result = arr.data.reduce((c, v) => {
  let l = v.data.charAt(3); //Get the 4th chatacter
  c[l] = c[l] || [];
  c[l].push(v);
  return c;
}, {});

console.log( result );

＆＃13;

＆＃13;

＆＃13;