我需要找到接下来的30天并放入数组以重复调度代码。
所以我需要为
设一个变量$ date =＆＃34;会保留日期＆＃34 ;; $ day_of_week =＆＃34;将保留星期几的＃值＆＃34 ;;
我不知道从哪里开始......我想在每个日子重复以下代码，以安排接下来30天的工作人员。
<?
// Connection Script
include 'connection.php';
date_default_timezone_set("America/New_York");
$tomorrow= strtotime('+ 1 day');
$date= date('N', $tomorrow);
// Get all employees who work tomorrow and group by unit//
$units= "select e.user_id, e.station, e.full_name, max(e.level) level, es.unit, es.days, es.start_time, es.end_time from employees e
left join employee_schedule es on es.pid = e.user_id
where es.days like '%$date%' and e.status = 1
group by es.unit";
$units_result= $conn->query($units);
//Roll through all employees who work tomorrow and place then in appropriate unit.
while($row_unit = $units_result->fetch_assoc()) {
if($row_unit['level'] == 3){
$level= 1;
}elseif($row_unit['level'] == 4){
$level= 2;
}elseif($row_unit['level'] == 5){
$level= 3;
}elseif($row_unit['level'] == 8){
$level= 4;
}
//Get Unit ID from each group
$unitid = $row_unit['unit'];
$intime= date('Y-m-d', $tomorrow);
$intime= $intime.' '. $row_unit['start_time'];
$length= '+ 23 hours';
$intimes= strtotime("$intime");
$endtime= strtotime("$length","$intimes" );
$endtime= date('Y-m-d H:i:s', $endtime);
$station= $row_unit['station'];
$timenow= date('Y-m-d H:i:s');
echo "<p>I am scheduling unit number $unitid to be on at $intime and leave at $endtime </p>";
$unitinsert= "insert into schedules (date_time, unit, level_of_service, start_time, end_time, station)
values ('$timenow', $unitid, $level , '$intime', '$endtime', $station)";
if(mysqli_query($conn, $unitinsert)){
echo "Records inserted successfully.";
$unitinid= $conn->insert_id;
echo $unitinid;
} else{
echo "ERROR: Could not able to execute $unitinsert. " . mysqli_error($conn);
}
$employee = "select e.*, es.unit, es.days, pc.email as pemail from employees e
left join employee_schedule es on es.pid = e.user_id
left join phone_carriers pc on pc.id = e.phone_carrier
where es.days like '%$date%'and es.unit = $unitid and e.status = 1";
$employee_result= $conn->query($employee);
if(mysqli_num_rows($employee_result) > 0){
while($row_employee = $employee_result->fetch_assoc()) {
$pid = $unitinid;
$eid= $row_employee['user_id'];
$ephone = $row_employee['mobile_number'];
$emailphone= $row_employee['mobile_number'].''. $row_employee['pemail'];
$unitcrewinsert= "insert into crew_assignment (date_time, pid, crew_member, phone_number, message_number, confirmed)
values ('$timenow', $pid, $eid , '$ephone', '$emailphone', 0)";
if(mysqli_query($conn, $unitcrewinsert)){
echo "Records inserted successfully.";
echo '<p> Crew Inserted </p>';
} else{
echo "<p>ERROR: Could not able to execute $unitinsert. " . mysqli_error($conn).'</p>';
}
}
}
}
答案 0 :(得分：0)
您最好的选择是提供开始日期和结束日期，并获取它们之间的天数。然后，这只是循环每一天并将其分配给数组的问题。也许可以使用相同的逻辑来解决周。
示例：
/home/user答案 1 :(得分：0)
我不确定这是最好的方式，但它有效。
<?php
include 'connection.php';
date_default_timezone_set("America/New_York");
// Start date
$date = '2018-05-18';
// End date
$end_date = '2018-05-31';
while (strtotime($date) <= strtotime($end_date)) {
$date = date("Y-m-d", strtotime("+1 day", strtotime($date)));
$dayn = date('N', strtotime($date));
echo "<p> $date </p>";
echo "<p> $dayn </p>";
$units = "select e.user_id, e.station, e.full_name, max(e.level) level, es.unit, es.days, es.start_time, es.total_hours from employees e
left join employee_schedule es on es.pid = e.user_id
where es.days like '%$dayn%' and e.status = 1
group by es.unit";
$units_result = $conn->query($units);
//Roll through all employees who work tomorrow and place then in appropriate unit.
if($units_result->num_rows > 0){
while ($row_unit = $units_result->fetch_assoc()) {
if ($row_unit['level'] == 3) {
$level = 1;
} elseif ($row_unit['level'] == 4) {
$level = 2;
} elseif ($row_unit['level'] == 5) {
$level = 3;
} elseif ($row_unit['level'] == 8) {
$level = 4;
}
//Get Unit ID from each group
$unitid = $row_unit['unit'];
$intime = $date . ' ' . $row_unit['start_time'];
$total_hours= $row_unit['total_hours'];
$length = "+ $total_hours ";
$intimes = strtotime("$intime");
$endtime = strtotime("$length", "$intimes");
$endtime = date('Y-m-d H:i:s', $endtime);
$station = $row_unit['station'];
$timenow = date('Y-m-d H:i:s');
echo "<p>I am scheduling unit number $unitid to be on at $intime and leave at $total_hours </p>";
$unitinsert = "insert into schedules (date_time, unit, level_of_service, start_time, total_hours, station)
values ('$timenow', $unitid, $level , '$intime', '$total_hours', $station)";
if (mysqli_query($conn, $unitinsert)) {
echo "Records inserted successfully.";
$unitinid = $conn->insert_id;
echo $unitinid;
} else {
echo "ERROR: Could not able to execute $unitinsert. " . mysqli_error($conn);
}
$inspectioninsert= ""
$employee = "select e.*, es.unit, es.days, pc.email as pemail from employees e
left join employee_schedule es on es.pid = e.user_id
left join phone_carriers pc on pc.id = e.phone_carrier
where es.days like '%$dayn%'and es.unit = $unitid and e.status = 1";
$employee_result = $conn->query($employee);
if (mysqli_num_rows($employee_result) > 0) {
while ($row_employee = $employee_result->fetch_assoc()) {
$pid = $unitinid;
$eid = $row_employee['user_id'];
$ephone = $row_employee['mobile_number'];
$emailphone = $row_employee['mobile_number'] . '' . $row_employee['pemail'];
$unitcrewinsert = "insert into crew_assignment (date_time, pid, crew_member, phone_number, message_number, confirmed)
values ('$timenow', $pid, $eid , '$ephone', '$emailphone', 0)";
if (mysqli_query($conn, $unitcrewinsert)) {
echo "Records inserted successfully.";
echo '<p> Crew Inserted </p>';
} else {
echo "<p>ERROR: Could not able to execute $unitinsert. " . mysqli_error($conn) . '</p>';
}
}
}
}
}
}
?>