Question

我有一个变量，例如this is a sentence的句子。我有一个MySQL数据库，其中包含一行包含以下内容的行：

"random sentences" 
"few random words" 
"this is cool"
"a car" 
"nice placement"

我需要打印出数据库行中存在的句子中出现的任何单词。对于上面给出的例句，结果将是：

"random sentences" 
"this is cool" 
"a car"

这是我到目前为止所尝试的：

<?php
$servername = "localhost";
$username = "dsfdsfds";
$password = "sdfdfsdsf";
$dbname = "sdf";

$conn = new mysqli($servername, $username, $password, $dbname);

if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}

$galleries = "This is a sentence";
$sql = "
SELECT * 
  FROM rawwords 
 WHERE origin LIKE '%" . $galleries. "%'
";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
    while($row = $result->fetch_assoc()) {
        echo "id: " . $row["id"]. " - location: " . $row["sentence"]. " <br><br>";
    }
} else {
    echo "0 results";
}

$conn->close();
?>

Answer 1

创建正确的sql：D

$galleries ="This is a sentence";
$arr = explode(" ", $galleries);

$sql = "SELECT * FROM rawwords WHERE origin LIKE";

$lenght = count($arr);

for ($i=0; $i<$lenght; $i++) {
    if ($i == 0) {
        $sql .=" '% " . $arr[$i]. " %'";
    } else {
        $sql .=" or '% " . $arr[$i]. " %'";
    }
}

Answer 2

您可以使用REGEXP使用[[:<:]]word[[:>:]]（字边界）来判断句子中的单词。您可以拆分字符串以获取单词，然后使用array_map()转换它们以进行查询。最后，您可以将implode()与" or "胶水一起使用：

$galleries = "This is a sentence" ;
$words = preg_split('~\W~', $galleries, -1, PREG_SPLIT_NO_EMPTY);

$words = array_map(function($word) { 
    return ' origin REGEXP "[[:<:]]'.$word.'[[:>:]]" '; 
}, $words);
$where = implode(' OR ', $words);

$sql = "SELECT * FROM rawwords WHERE $where";

将生成查询：

SELECT * FROM rawwords 
WHERE origin REGEXP "[[:<:]]This[[:>:]]" 
   OR origin REGEXP "[[:<:]]is[[:>:]]" 
   OR origin REGEXP "[[:<:]]a[[:>:]]" 
   OR origin REGEXP "[[:<:]]sentence[[:>:]]"

重要，您应该仔细查看参数化查询请阅读本文，其中包含几个示例：How can I prevent SQL injection in PHP?

将句子分成单词并检查MySQL是否出现

2 个答案: