Question

我必须从JSON文件中检索数据，然后将其分配给数组。但是我收到了一个错误

＆＃34;无法设置属性＆＃39; ref＆＃39;未定义＆＃34;。

将JSON转换为关联数组或对象。

 var items2=[[]]; 
 $.getJSON("results.json", function( data ) {
      $.each( data, function( key, val ) {
                if(key=="items")
                {
                    $.each(val,function(keyScd,valScd)
                    {
                        $.each(valScd,function(keyTrd,valTrd)
                    {
                        var ref=JSON.stringify(valTrd.ref).slice(1,-1);
                        var prix=JSON.stringify(valTrd.prix).slice(1,-1);
                        var taille=JSON.stringify(valTrd.taille).slice(1,-1);

                        items2[keyScd][keyTrd]["ref"]=ref;
                        items2[keyScd][keyTrd]["prix"]=prix;
                        items2[keyScd][keyTrd]["taille"]=taille;


                     });
                 });
                }
                else
                {
                        items2[key]=val;
                }
            });
        });

这是我的JSON

  {  
       "items":[  
          [  
             {  
                "ref":"cpe-zfmmpx23",
                "nomc":"1",
                "description":"yellow sofa",
                "dispo":"1",
                "prix":"300",
                "taille":"standard",
                "couleur":"jaune"
             },
             {  
                "ref":"cpe-zfmmpx23",
                "nomc":"2",
                "description":"yellow sofa",
                "dispo":"1",
                "prix":"400",
                "taille":"0.5mH,2mW",
                "couleur":"red"
             }
          ]
       ],
       "buildNumber":"fa36b5153f33240a111e6dc336a70"
    }

Answer 1

您应该能够映射元素。这就是你要追求的吗？

var temp = `{"items":[[{"ref":"cpe-zfmmpx23","nomc":"1","description":"yellow sofa","dispo":"1","prix":"300","taille":"standard","couleur":"jaune"},{"ref":"cpe-zfmmpx23","nomc":"2","description":"yellow sofa","dispo":"1","prix":"400","taille":"0.5mH,2mW","couleur":"red"}]],"buildNumber":"fa36b5153f33240a111e6dc336a70"}
`;

var data = JSON.parse(temp);
var items2;

if (data.items) {
  items2 = $.map(data.items, function(items) {
    return $.map(items, function(item) {
      return {
        ref: item.ref.slice(1, -1),
        prix: item.prix.slice(1, -1),
        taille: item.taille.slice(1, -1)
      };
    });
  });
}

console.log(items2);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

Answer 2

这是另一种方法，不需要在那里使用jquery：

＆＃13;

const json = '{"items":[[{"ref":"cpe-zfmmpx23","nomc":"1","description":"yellow sofa","dispo":"1","prix":"300","taille":"standard","couleur":"jaune"},{"ref":"cpe-zfmmpx23","nomc":"2","description":"yellow sofa","dispo":"1","prix":"400","taille":"0.5mH,2mW","couleur":"red"}]],"buildNumber":"fa36b5153f33240a111e6dc336a70"}';

const newJson = JSON.parse(json);
(newJson.items).forEach((data) => {
  data.forEach((newData) => {
    console.log(newData.ref)
    });
});

＆＃13;

关联数组：不能设置undefined的属性

2 个答案: