Question

我尝试记录除了用户，_id等之外的数组中的每个名称。执行if(!word === "users")工作并按照我的预期记录用户条目。我可能会忽略一些微不足道的事情，并提前道歉。谢谢。

let arr = ["noun","nounoffensive","nounvulgar","adjective","verb","verbinformal","conjunction","exclamation","users","_id","word","createdAt","updatedAt","__v"]

arr.forEach((word)=>{
    if(!word === "users" || "_id" || "word" || "createdAt" || "updatedAt"){
        console.log(word)
    };
});

Answer 1

您的if声明不正确。您缺少word ===进行其他比较，!应该存在整个表达式。

＆＃13;

let arr = ["noun","nounoffensive","nounvulgar","adjective","verb","verbinformal","conjunction","exclamation","users","_id","word","createdAt","updatedAt","__v"]

arr.forEach((word)=>{
    if(!(word === "users" || word === "_id" || word === "word" || word === "createdAt" || word === "updatedAt")){
        console.log(word)
    };
});

＆＃13;

替代方法也可以是创建一个数组，例如let notInArray = ["users", "_id", "word", "createdAt", "updatedAt"];，其中包含您要排除的单词：

＆＃13;

let arr = ["noun","nounoffensive","nounvulgar","adjective","verb","verbinformal","conjunction","exclamation","users","_id","word","createdAt","updatedAt","__v"]

let notInArray = ["users", "_id", "word", "createdAt", "updatedAt"];
arr.forEach((word)=>{
  if(notInArray.indexOf(word) === -1){
    console.log(word)
  };
});

＆＃13;

Answer 2

你不能使用

if(!word === "users" || "_id" || "word" || "createdAt" || "updatedAt")

好像是陈述。

您可以使用数组来检查它是否在里面：

let arr = ["noun","nounoffensive","nounvulgar","adjective","verb","verbinformal","conjunction","exclamation","users","_id","word","createdAt","updatedAt","__v"]
const words2find = ['users', '_id', 'word', 'createdAt', 'updatedAt'];

arr.forEach((word)=>{
    if(words2find.indexOf(word) < 0){
        console.log(word)
    };
});

如果在检查数组是否包含单词时，语句返回undefined

2 个答案: