Question

所以我有这个数据

const data = [
  {
    "employee_name": "Employee A",
    "commission_date": "14/05/2018",
    "commission_price": 9000
  },
  {
    "employee_name": "Employee A",
    "commission_date": "17/05/2018",
    "commission_price": 5000
  },
  {
    "employee_name": "Employee B",
    "commission_date": "18/05/2018",
    "commission_price": 2000
  },
  {
    "employee_name": "Employee B",
    "commission_date": "18/05/2018",
    "commission_price": 5000
  },
  {
    "employee_name": "Employee B",
    "commission_date": "19/05/2018",
    "commission_price": 500
  }
]

我想根据数据匹配commission_price和employee_name

计算commission_date

这里是预期的输出：

[
  {
    "employee_name": "Employee A",
    "commission_date": "14/05/2018",
    "commission_price": 9000
  },
  {
    "employee_name": "Employee A",
    "commission_date": "17/05/2018",
    "commission_price": 5000
  },
  {
    "employee_name": "Employee B",
    "commission_date": "18/05/2018",
    "commission_price": 7000
  },
  {
    "employee_name": "Employee B",
    "commission_date": "19/05/2018",
    "commission_price": 500
  }
]

我尝试过基于类似问题的答案，但结果仅根据employee_name计算。这里是代码

let result = Object.values(data.reduce((r, { employee_name, commission_price }) => {
  r[employee_name] = r[employee_name] || { employee_name, commission_price : 0 }
  r[employee_name].commission_price += commission_price
  return r
}, {}))

谢谢。

Answer 1

您可以将组合键用于任意数量的组。

var data = [{ employee_name: "Employee A", commission_date: "14/05/2018", commission_price: 9000 }, { employee_name: "Employee A", commission_date: "17/05/2018", commission_price: 5000 }, { employee_name: "Employee B", commission_date: "18/05/2018", commission_price: 2000 }, { employee_name: "Employee B", commission_date: "18/05/2018", commission_price: 5000 }, { employee_name: "Employee B", commission_date: "19/05/2018", commission_price: 500 }],
    result = Object.values(data.reduce((r, o) => {
        var key = ['employee_name', 'commission_date'].map(k => o[k]).join('|');
        r[key] = r[key] || { employee_name: o.employee_name, commission_date: o.commission_date, commission_price : 0 };
        r[key].commission_price += o.commission_price;
        return r;
    }, {}));

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

在数组javascript中过滤，匹配，从日期和名称计算

1 个答案: