再次询问，但希望更清楚。我有以下情况，这是完美的工作你可以看到Sql Unions Part 1原来的问题得到了解答！
DECLARE @imvw_woap_code_with_cust TABLE (
pkey INT,
Code_id VARCHAR(200),
code_type_id VARCHAR(200),
asset_standard_id VARCHAR(200),
date_completed DATETIME
)
INSERT INTO @imvw_woap_code_with_cust(pkey,Code_id,code_type_id,asset_standard_id,date_completed)
SELECT 101480,'Alarmining','A-Problem','1 East','2017-08-10 02:00:30.013'
UNION SELECT 103350,'Fluid/Gas Leak (Out)','A-Problem','2 west','2017-08-10 02:00:30.013'
UNION SELECT 104033,'plug/Pwr Cord Damg','A-Problem','2 west','2017-08-10 02:00:30.013'
UNION SELECT 107296,'Alarmining','A-Problem','2 west','2017-09-11 02:00:30.013'
UNION SELECT 106404,'Incoming Inspect','A-Problem','2 west','2017-08-10 02:00:30.013'
UNION SELECT 106407,'Incoming Inspect','A-Problem','2 west','2017-09-11 02:00:30.013'
UNION SELECT 106408,'Incoming Inspect','A-Problem','2 west','2017-09-12 02:00:30.013'
DECLARE @IMTBL_CODE TABLE (
pkey INT,
Code_id VARCHAR(200),
code_type_id VARCHAR(200)
)
INSERT INTO @IMTBL_CODE(pkey,Code_id,code_type_id)
SELECT 100064,'1-NO PROBLEM CODE ENTERED','A-Problem'
UNION SELECT 100068,'Alarmining','A-Problem'
UNION SELECT 100069,'Battery Failure','A-Problem'
UNION SELECT 100070,'Incoming Inspect','A-Problem'
UNION SELECT 100071,'Fluid/Gas Leak (Out)','A-Problem'
UNION SELECT 100072,'Case Damaged','A-Problem'
UNION SELECT 100073,'plug/Pwr Cord Damg','A-Problem'
CREATE VIEW cause_codes as
SELECT
possibilities.code_id AS code_id,
possibilities.asset_standard_id,
Count(U.pkey) AS [COUNT]
FROM (
SELECT
a.asset_standard_id,b.code_id
FROM (SELECT DISTINCT asset_standard_id FROM @imvw_woap_code_with_cust) AS a
CROSS JOIN (
SELECT DISTINCT code_id FROM @imtbl_code
UNION
SELECT DISTINCT CODE_ID AS [ID] FROM @imvw_woap_code_with_cust
) AS b
) AS possibilities
LEFT OUTER JOIN @imvw_woap_code_with_cust AS U ON U.code_id = possibilities.code_id
AND possibilities.asset_standard_id=u.asset_standard_id
and u.code_type_id='A-Problem'
GROUP BY possibilities.code_id, possibilities.asset_standard_id
order by [count]
一旦我将它创建到视图（cause_codes）中，它就会返回一个整齐的表，其中包含代码出现次数（包括0次计数）。
CODE ID asset_standard_id count
1-NO PROBLEM CODE ENTERED 1 East 0
1-NO PROBLEM CODE ENTERED 2 west 0
Battery Failure 1 East 0
Battery Failure 2 west 0
Case Damaged 1 East 0
Case Damaged 2 west 0
Fluid/Gas Leak (Out) 1 East 0
Incoming Inspect 1 East 0
plug/Pwr Cord Damg 1 East 0
plug/Pwr Cord Damg 2 west 1
Fluid/Gas Leak (Out) 2 west 1
Alarmining 1 East 1
Alarmining 2 west 1
Incoming Inspect 2 west 3
然后客户回来了，希望添加日期 所以，如果我在视图中添加日期
ALTER VIEW cause_codes as
SELECT
possibilities.code_id AS code_id,
possibilities.asset_standard_id,
Count(U.pkey) AS [COUNT],
U.date_created
FROM (
SELECT
a.asset_standard_id,b.code_id
FROM (SELECT DISTINCT asset_standard_id FROM @imvw_woap_code_with_cust) AS a
CROSS JOIN (
SELECT DISTINCT code_id FROM @imtbl_code
UNION
SELECT DISTINCT CODE_ID AS [ID] FROM @imvw_woap_code_with_cust
) AS b
) AS possibilities
LEFT OUTER JOIN @imvw_woap_code_with_cust AS U ON U.code_id = possibilities.code_id
AND possibilities.asset_standard_id=u.asset_standard_id
and u.code_type_id='A-Problem'
GROUP BY possibilities.code_id, possibilities.asset_standard_id,date_created
order by [count]
然后进行搜索
select * from cause_codes where asset_standard_id = '2 west' and date_completed > '2017-09-10 02:00:30.013' and date_completed < '2017-09-12 02:00:30.013'
表格分割这样的行 - ＆gt;
Incoming Inspect 2 west 1 2017-09-11 02:00:30.013'
Incoming Inspect 2 west 1 2017-09-12 02:00:30.013'
有没有办法可以执行此操作（添加搜索日期），但仍然保持单行的正确计数？
我希望这很清楚......这是一个很大的问题。 感谢您抽出宝贵时间阅读我的书：）
答案 0 :(得分：0)
每当按日期分组，并且日期有多个唯一值时，您将获得每个日期的多行，每个唯一日期的分组总和。请注意，您现在要求为每个代码，资产ID和日期提供汇总摘要数据。
您必须获取新日期值的最小值或最大值（不同的摘要），而不是按日期分组，或者如果您愿意，并且您确定不会获得大量日期，如果你想这样做，你可以在逗号描述的列表中列出它们可能的行日期。以下是使用For Xml技巧的其他表的日期列表的示例。网上还有其他例子。
select
RepName, DateList
from
(
select
FirstName + ' ' + LastName as RepName, PersonID
from
Person
where
PersonID in (23164,30637,29985,25643)
) as p
cross apply (
select stuff ( (
select
', ' + convert(varchar(16), CallDate, 101)
from
(
select
distinct TheDate
from
dbo.Info as c
inner join Person as p2 on p2.PersonID = c.PersonID
where
p2.PersonID = p.PersonID
) as dat
order by CallDate
for xml path('')
), 1, 2, '') as DateList
) as dateList
答案 1 :(得分：0)
我首先到达那里，我没有衡量表现。
;WITH Activity As
(
SELECT Count = COUNT(*),Customer.Code_id,Customer.asset_standard_id
FROM @imvw_woap_code_with_cust Customer
GROUP BY Customer.Code_id,asset_standard_id
),
Groups AS
(
SELECT Code_id,asset_standard_id
FROM @IMTBL_CODE Codes
CROSS APPLY (SELECT DISTINCT asset_standard_id FROM @imvw_woap_code_with_cust) X
),
GroupedActivity AS
(
SELECT Groups.Code_id,Groups.asset_standard_id,Count = CASE WHEN Activity.Count IS NULL THEN 0 ELSE Activity.Count END
FROM Groups
LEFT OUTER JOIN Activity ON Activity.Code_id = Groups.Code_id AND Activity.asset_standard_id = Groups.asset_standard_id
)
SELECT
C.pkey,
G.Code_id,
G.asset_standard_id,
G.Count,
C.date_completed
FROM
@imvw_woap_code_with_cust C
INNER JOIN GroupedActivity G ON G.Code_id = C.Code_id AND G.asset_standard_id = C.asset_standard_id
WHERE
G.asset_standard_id = '2 west' and date_completed > '2017-09-10 02:00:30.013' and date_completed < '2017-09-12 02:00:30.013'
如果可以省略没有活动的标准，可以缩短到下面的查询。
;WITH Activity As
(
SELECT Count = COUNT(*),Customer.Code_id,Customer.asset_standard_id
FROM @imvw_woap_code_with_cust Customer
GROUP BY Customer.Code_id,asset_standard_id
)
SELECT
C.pkey,
G.Code_id,
G.asset_standard_id,
G.Count,
C.date_completed
FROM
@imvw_woap_code_with_cust C
INNER JOIN Activity G ON G.Code_id = C.Code_id AND G.asset_standard_id = C.asset_standard_id
WHERE
G.asset_standard_id = '2 west' and date_completed > '2017-09-10 02:00:30.013' and date_completed < '2017-09-12 02:00:30.013'
使用您在上面发布的那个包含在CTE中并删除了date_completed的相同查询。当计数与细节对齐时，您可以覆盖最终查询中完成的日期。
;WITH GroupedData AS
(
SELECT
possibilities.code_id AS code_id,
possibilities.asset_standard_id,
Count(U.pkey) AS [COUNT]
FROM (
SELECT
a.asset_standard_id,b.code_id
FROM (SELECT DISTINCT asset_standard_id FROM @imvw_woap_code_with_cust) AS a
CROSS JOIN (
SELECT DISTINCT code_id FROM @imtbl_code
UNION
SELECT DISTINCT CODE_ID AS [ID] FROM @imvw_woap_code_with_cust
) AS b
) AS possibilities
LEFT OUTER JOIN @imvw_woap_code_with_cust AS U ON U.code_id = possibilities.code_id
AND possibilities.asset_standard_id=u.asset_standard_id
and u.code_type_id='A-Problem'
GROUP BY possibilities.code_id, possibilities.asset_standard_id
)
SELECT
G.code_id,
G.asset_standard_id,
G.COUNT
C.date_completed
FROM
@imvw_woap_code_with_cust C
INNER JOIN GroupedData G ON G.Code_id = C.Code_id AND G.asset_standard_id = C.asset_standard_id
ORDER BY count