Question

我正在尝试推送通知。所以当我在firebase上部署我的代码时，当我尝试上传firebase函数时，我收到以下错误

这是我终端中显示的错误：

   22:14  warning  Avoid nesting promises                      promise/no-nesting
   22:69  error    Each then() should return a value or throw  promise/always-return

   ✖ 2 problems (1 error, 1 warning)

   npm ERR! code ELIFECYCLE
   npm ERR! errno 1
   npm ERR! functions@ lint: `eslint .`
   npm ERR! Exit status 1
   npm ERR! 
   npm ERR! Failed at the functions@ lint script.
   npm ERR! This is probably not a problem with npm. There is likely additional logging output above.

   npm ERR! A complete log of this run can be found in:
   npm ERR!     /Users/mac/.npm/_logs/2018-05-17T17_45_54_673Z-debug.log

   Error: functions predeploy error: Command terminated with non-zero exit code1

javascript代码：

'use strict'
const functions = require('firebase-functions');
const admin = require('firebase-admin');
admin.initializeApp(functions.config().firebase);
exports.sendNotification =functions.database.ref('/notifications/{user_id}/{notification_id}').onWrite((change, context) => {
        const user_id = context.params.user_id;
        const notification = context.params.notification;
        console.log('The User Id is : ', user_id);
        if(!event.data.vall()){
            return console.log('A notification has been deleted from the database : ',notification_id);
        }
        const deviceToken = admin.database().ref(`/Users/${user_id}/device_token`).once('value');
            return deviceToken.then(result =>{
                        const token_id = result.val();
                        const payload = {
                            notification: {
                                title : "Friend Request",
                                body : "You have received a new Friend Request",
                                icon : "default"
                            }
                        };
             return admin.messaging().sendToDevice(token_id, payload).then(response =>{
                console.log("This was the notification Feature");
                    });
        });
});

如何解决？

Answer 1

你有两个回报：

return return admin.messaging().sendToDevice(token_id, payload).then(response =>{ console.log("This was the notification Feature"); });

替换：

return admin.messaging().sendToDevice(token_id, payload).then(response =>{
            console.log("This was the notification Feature");
                });

Answer 2

答案很简单，每个应该返回一个值
您必须添加

之类的return语句

返回响应

复制并粘贴此代码即可使用

“严格使用”
  const functions = require（'firebase-functions'）;
  const admin = require（'firebase-admin'）;
  admin.initializeApp（functions.config（）。firebase）;
  Exports.sendNotification = functions.database.ref（'/ notifications / {user_id}
/{notification_id}').onWrite((change，context）=> {
      const user_id = context.params.user_id;
      const notification = context.params.notification;
      console.log（'用户ID为：'，user_id）;
      如果（！event.data.vall（））{
          return console.log（'通知已从数据库中删除：'，notification_id）;
      }
      const deviceToken = admin.database（）。ref（/Users/${user_id}<br>/device_token）。once（'value'）;
      return deviceToken.then（result => {
          const token_id = result.val（）;
          const有效负载= {
              通知：{
                  标题：“好友请求”，
                  正文：“您收到了新的朋友请求”，
                  图标：“默认”
              }
          };
          返回admin.messaging（）。sendToDevice（token_id，有效负载）
          .then（response => {
              console.log（“这是通知功能”）;
              返回响应
          }）;
      }）;
  }）;

FireBase错误解析错误：意外的令牌返回

2 个答案: