Question

这里有一个和弦列表：

chordList = ["N","C:maj","C:min","C#:maj","C#:min","D:maj","D:min","D#:maj","D#:min","E:maj","E:min","F:maj","F:min","F#:maj","F#:min","G:maj","G:min","G#:maj","G#min","A:maj","A:min","A#:maj", "A#:min", "B:maj","B:min"]

然后，例如，有一些字符串，如＆＃34; F：maj＆＃34;，＆＃34; F：maj / 3＆＃34;，＆＃34; C：maj / 4＆＃34;，＆＃34; d：min7＆＃34;我知道我可以使用chordList中的字符串来检查列表中是否有正常的和弦。但是，我想比较像＆＃34; F：maj / 3＆＃34;，＆＃34; C：maj / 4＆＃34;使用列表中的字符串，它们是否具有共同的＆＃34; x：maj＆＃34;或者＆＃34; x：min＆＃34;部件，然后返回TRUE或FALSE值

Answer 1

我建议您将chordList转换为set，以获得平均O(1)次查找时间。

选项1
split上的 / ：

sample = 'C:maj/7'
sample.split('/')[0] in chordList
# True

选项2 （如果我在钢琴演奏时间记得正确，这将永远有效，但如果和弦存在于9日以上则会失败）
的 slice

sample = 'C:maj/7' sample[:-2] in chordList # True

Answer 2

似乎你可以通过前缀匹配字符串：

s="F:maj/3"
if any(s.startswith(x) or x.startswith(s) for x in chordList):
    # yes, it is contained

Python：字符串比较

2 个答案: