给定一个JSONB对象是否有一个为每个键生成列的函数？

Question

CREATE TABLE data (obj JSONB);
INSERT INTO data (obj) VALUES ('{"a": 1, "b": 2}'::jsonb);
INSERT INTO data (obj) VALUES ('{"a": 3, "b": 4}'::jsonb);

我需要一个产生以下结果的查询：

 a | b 
---|---
 1 | 2
 3 | 4

编辑：回答

SELECT x.* 
FROM data, jsonb_to_record(obj) as x(a text, b text);

Answer 1

尝试类似......

CREATE TABLE lame (stuff jsonb);
INSERT INTO lame VALUES ('{"a" : 1, "b": 1}');
INSERT INTO lame VALUES ('{"a" : 2, "b": 2}');
SELECT stuff->'a' as "a", stuff->'b' as "b" FROM lame;

查找文章Faster Operations with the JSONB Data Type in PostgreSQL中的提示。

祝你好运！