Question

我尝试了这个，但它没有工作，请给出解决方案......

select DATE_FORMAT(patient_blood_sugar_record_date,'%a')as Pdate,patient_blood_sugar_Pre_fasting
    from
    (
      select patient_blood_sugar_record_date,patient_blood_sugar_Pre_fasting
      from patient_blood_sugar_record
      where patient_blood_sugar_record_date BETWEEN date_add(curdate(), interval -6 day) AND curdate()
      group by patient_blood_sugar_record_date
      union all
      select curdate(), 0
      union all
      select date_add(curdate(), interval -1 day), 0
      union all
      select date_add(curdate(), interval -2 day), 0
      union all
      select date_add(curdate(), interval -3 day), 0
      union all
      select date_add(curdate(), interval -4 day), 0
      union all
      select date_add(curdate(), interval -5 day), 0
      union all
      select date_add(curdate(), interval -6 day), 0
    ) x
    group by patient_blood_sugar_record_date
    order by patient_blood_sugar_record_date;

Answer 1

请在下面示例： -

SELECT * FROM table WHERE date_column＆gt; =（CURDATE（） - INTERVAL 10 DAY）

Answer 2

试试这个。它具有LEFT JOIN，可以提供您想要的结果。

select DATE_FORMAT(f.dts,'%a') as Pdate,ifnull(patient_blood_sugar_Pre_fasting,0) patient_blood_sugar_Pre_fasting 
from (select curdate() dts
    union all
    select date_add(curdate(), interval -1 day)
    union all
    select date_add(curdate(), interval -2 day)
    union all
    select date_add(curdate(), interval -3 day)
    union all
    select date_add(curdate(), interval -4 day)
    union all
    select date_add(curdate(), interval -5 day)
    union all
    select date_add(curdate(), interval -6 day)) f
left join
    (select date_format(patient_blood_sugar_record_date,'%a') patient_blood_sugar_record_date,
            min(patient_blood_sugar_Pre_fasting) patient_blood_sugar_Pre_fasting
      from patient_blood_sugar_record
      where patient_blood_sugar_record_date BETWEEN date_add(curdate(), interval -6 day) AND curdate()
      group by date_format(patient_blood_sugar_record_date,'%a')
    ) x
on DATE_FORMAT(f.dts,'%a') = patient_blood_sugar_record_date
order by patient_blood_sugar_record_date;

如果在特定日期没有值返回0，如何在mysql中获取最近7天的记录

2 个答案: