我有一个我编写的AppleScript来对Mail.app消息进行一些解析,但似乎我需要比AppleScript提供的更强大的处理(特别是 - 从它引用的原始消息中分离回复的消息)(比如说,使用Python的email
包。是否可以将电子邮件作为MIME字符串获取?
答案 0 :(得分:1)
我不确定这是不是您的意思,但是您可以通过以下方式获取您在Mail.app中所做的选择中的原始邮件文本,而这些选择可以使用MIME工具进行处理。提取所有部分。
<div class="contato">
<form name="contato" method="POST" netlify>
<div class="header">
<h1>Contato</h1>
</div>
<div class="preencher">
<p>
<label>Nome: <input type="text" name="nome"></label>
</p>
<p>
<label>E-mail: <input type="email" name="email"></label>
</p>
<p>
<label>Empresa/site: <input cols="60" type="email" name="empresa"></label>
</p>
<p>
<label>Mensagem: <textarea name="mensagem"></textarea></label>
</p>
<p>
<button type="submit">Send</button>
</p>
</div>
</form>
</div>
然后这是一个Python电子邮件示例脚本,它解压缩消息并将每个MIME部分写入目录中的单独文件
https://docs.python.org/3.4/library/email-examples.html
tell application "Mail"
set msgs to selection
if length of msgs is not 0 then
repeat with msg in msgs
set messageSource to source of msg
set textFile to "/Users/harley/Desktop/foo.txt"
set myFile to open for access textFile with write permission
write messageSource to myFile
close access myFile
end repeat
end if
end tell
那么如果unpack.py脚本在AppleScript输出上运行......
#!/usr/bin/env python3
"""Unpack a MIME message into a directory of files."""
import os
import sys
import email
import errno
import mimetypes
from argparse import ArgumentParser
def main():
parser = ArgumentParser(description="""\
Unpack a MIME message into a directory of files.
""")
parser.add_argument('-d', '--directory', required=True,
help="""Unpack the MIME message into the named
directory, which will be created if it doesn't already
exist.""")
parser.add_argument('msgfile')
args = parser.parse_args()
with open(args.msgfile) as fp:
msg = email.message_from_file(fp)
try:
os.mkdir(args.directory)
except FileExistsError:
pass
counter = 1
for part in msg.walk():
# multipart/* are just containers
if part.get_content_maintype() == 'multipart':
continue
# Applications should really sanitize the given filename so that an
# email message can't be used to overwrite important files
filename = part.get_filename()
if not filename:
ext = mimetypes.guess_extension(part.get_content_type())
if not ext:
# Use a generic bag-of-bits extension
ext = '.bin'
filename = 'part-%03d%s' % (counter, ext)
counter += 1
with open(os.path.join(args.directory, filename), 'wb') as fp:
fp.write(part.get_payload(decode=True))
if __name__ == '__main__':
main()
您将获得一个MIME部分分开的目录。当我在引用原始邮件的邮件上运行此邮件时,原始邮件将显示在单独的部分中。