Question

我想连续获取用户位置并在我的数据库中更新它。我正在使用FusedLocationApi来获取连续的位置更改。要获得用户必须打开的位置GPS和互联网连接必须在那里。保持GPS长时间转动并连续使用INTERNET是电池排水的罪魁祸首。所以我想知道如何使用最小电池电量并获取连续的位置变化。

这就是我获取位置的方式，

public class LocationActivity extends Activity implements
    LocationListener,
    GoogleApiClient.ConnectionCallbacks,
    GoogleApiClient.OnConnectionFailedListener {

private static final String TAG = "LocationActivity";
private static final long INTERVAL = 1000 * 10;
private static final long FASTEST_INTERVAL = 1000 * 5;
Button btnFusedLocation;
TextView tvLocation;
LocationRequest mLocationRequest;
GoogleApiClient mGoogleApiClient;
Location mCurrentLocation;
String mLastUpdateTime;

protected void createLocationRequest() {
    mLocationRequest = new LocationRequest();
    mLocationRequest.setInterval(INTERVAL);
    mLocationRequest.setFastestInterval(FASTEST_INTERVAL);
    mLocationRequest.setPriority(LocationRequest.PRIORITY_HIGH_ACCURACY);
}

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    Log.d(TAG, "onCreate ...............................");
    //show error dialog if GoolglePlayServices not available
    if (!isGooglePlayServicesAvailable()) {
        finish();
    }
    createLocationRequest();
    mGoogleApiClient = new GoogleApiClient.Builder(this)
            .addApi(LocationServices.API)
            .addConnectionCallbacks(this)
            .addOnConnectionFailedListener(this)
            .build();
    mGoogleApiClient.connect();  
    setContentView(R.layout.activity_main);
    tvLocation = (TextView) findViewById(R.id.tvLocation);

    btnFusedLocation = (Button) findViewById(R.id.btnShowLocation);
    btnFusedLocation.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View arg0) {
            updateUI();
        }
    });

}

@Override
public void onStart() {
    super.onStart();
    if (mGoogleApiClient.isConnected()) {
        startLocationUpdates();
        Log.d(TAG, "Location update resumed .....................");
    }
}

@Override
public void onStop() {
    super.onStop();
    Log.d(TAG, "onStop fired ..............");
    mGoogleApiClient.disconnect();
    Log.d(TAG, "isConnected ...............: " + mGoogleApiClient.isConnected());
}

private boolean isGooglePlayServicesAvailable() {
    int status = GooglePlayServicesUtil.isGooglePlayServicesAvailable(this);
    if (ConnectionResult.SUCCESS == status) {
        return true;
    } else {
        GooglePlayServicesUtil.getErrorDialog(status, this, 0).show();
        return false;
    }
}

@Override
public void onConnected(Bundle bundle) {
    Log.d(TAG, "onConnected - isConnected ...............: " + mGoogleApiClient.isConnected());
    startLocationUpdates();
}

protected void startLocationUpdates() {
    PendingResult<Status> pendingResult = LocationServices.FusedLocationApi.requestLocationUpdates(
            mGoogleApiClient, mLocationRequest, this);
    Log.d(TAG, "Location update started ..............: ");
}

@Override
public void onConnectionSuspended(int i) {

}

@Override
public void onConnectionFailed(ConnectionResult connectionResult) {
    Log.d(TAG, "Connection failed: " + connectionResult.toString());
}

@Override
public void onLocationChanged(Location location) {
    Log.d(TAG, "Firing onLocationChanged..............................................");
    mCurrentLocation = location;
    mLastUpdateTime = DateFormat.getTimeInstance().format(new Date());
    updateUI();
}

private void updateUI() {
    Log.d(TAG, "UI update initiated .............");
    if (null != mCurrentLocation) {
        String lat = String.valueOf(mCurrentLocation.getLatitude());
        String lng = String.valueOf(mCurrentLocation.getLongitude());
        tvLocation.setText("At Time: " + mLastUpdateTime + "\n" +
                "Latitude: " + lat + "\n" +
                "Longitude: " + lng + "\n" +
                "Accuracy: " + mCurrentLocation.getAccuracy() + "\n" +
                "Provider: " + mCurrentLocation.getProvider());
    } else {
        Log.d(TAG, "location is null ...............");
    }
}

@Override
protected void onPause() {
    super.onPause();
    stopLocationUpdates();
}

protected void stopLocationUpdates() {
    LocationServices.FusedLocationApi.removeLocationUpdates(
            mGoogleApiClient, this);
    Log.d(TAG, "Location update stopped .......................");
}

@Override
public void onResume() {
    super.onResume();
    if (mGoogleApiClient.isConnected()) {
        startLocationUpdates();
        Log.d(TAG, "Location update resumed .....................");
    }
}
}

Answer 1

https://developer.android.com/guide/topics/location/strategies

Google建议创建一个能够说明最佳效果的模型。解释链接的页面...

选择合适的时间开始收听所需位置提供商的更新。
维持目前的最佳估计值＆＃34;通过过滤掉新的但不太准确的修复来定位。
暂时停止侦听位置更新。
利用最后一次最佳位置估算。

持续的位置更改是解决问题的一种非常通用的方法，您需要为您的特定用例定义问题和解决方案。

通过减少电池排放来获取连续的位置变化

1 个答案: