Question

我有一本字典：

...

from functools import partial

torusCB.stateChanged.connect(partial(modifier.enableTorus))
coneCB.stateChanged.connect(partial(modifier.enableCone))
cylinderCB.stateChanged.connect(partial(modifier.enableCylinder))
cuboidCB.stateChanged.connect(partial(modifier.enableCuboid))
planeCB.stateChanged.connect(partial(modifier.enablePlane))
sphereCB.stateChanged.connect(partial(modifier.enableSphere))

...

我想将这个字典制成一个csv，最上面的键是最左边的列，子键是最上面一行的标题，每个后续行都用子键值填充：

dic = {"Location1":{"a":1,"b":2,"c":3},"Location2":{"a":4,"b":5,"c":6}}

我使用以下脚本成功完成了这项工作：

Location    a   b   c
Location1   1   2   3
Location2   4   5   6

奇怪的是，我将这个测试用例写入一个真实案例，并最终将我的位置键分配到其他列中。现在我的第一个想法很好，我必须搞砸了构建字典，但经过检查，我得到完全相同的字典格式，但更多的键值除外。但输出如

import csv

dic = {"Location1":{"a":1,"b":2,"c":3},"Location2":{"a":4,"b":5,"c":6}}
fields = ["Location","a","b","c"]

with open(r"C:\Users\tyler.cowan\Desktop\tabulated.csv", "w", newline='') as f:
    w = csv.DictWriter(f, extrasaction='ignore', fieldnames = fields)
    w.writeheader()
    for k in dic:
        w.writerow({field: dic[k].get(field) or k for field in fields})

以下是我的完整脚本

Location    a   b   c   d           e   f   g   h
Location1   1   2   3   Location1   7   8   9   10
Location2   4   5   6   Location2   2   3   4   5

，输入数据如下：

# -*- coding: utf-8 -*-

import os
import csv


def pretty(d, indent=0):
    #prettify dict for visual Inspection
   for key, value in d.items():
      print('\t' * indent + str(key))
      if isinstance(value, dict):
         pretty(value, indent+1)
      else:
         if value == "":
             print("fubar")
         print('\t' * (indent+1) + str(value))



inFolder = "Folder"
dirList = os.listdir(inFolder)

#print(dirList)
fields = [ 'Lat-Long']
allData = {}
for file in dirList:
    fname, ext = os.path.splitext(file)
    if fname not in fields:
        fields.append(fname)

    #handle .dat in this block
    if ext.lower() == ".dat":
        #print("found dat ext: " + str(ext))
        with open(os.path.join(inFolder,file), "r") as f:
            for row in f:
                try:
                    row1 = row.split(" ")
                    if str(row1[0])+"-"+str(row1[1]) not in allData:
                        allData[str(row1[0])+"-"+str(row1[1])] = {}
                    else:
                        allData[str(row1[0])+"-"+str(row1[1])][fname] = row1[2]

                except IndexError:
                    row2 = row.split("\t")
                    if str(row2[0])+"-"+str(row2[1]) not in allData:
                        allData[str(row2[0])+"-"+str(row2[1])] = {}
                    else:
                        allData[str(row2[0])+"-"+str(row2[1])][fname] = "NA"

    elif ext.lower() == ".csv":
        with open(os.path.join(inFolder,file), "r") as f:
            for row in f:
                row1 = row.split(",")
                if str(row1[0])+"-"+str(row1[1]) not in allData:
                    allData[str(row1[0])+"-"+str(row1[1])] = {}
                else:
                    allData[str(row1[0])+"-"+str(row1[1])][fname] = row1[2]



pretty(allData)

with open("testBS.csv", "w", newline='') as f:
    w = csv.DictWriter(f, extrasaction='ignore', fieldnames = fields)
    w.writeheader()
    for k in allData:
        w.writerow({field: allData[k].get(field) or k for field in fields})

我想弄清楚如何诊断和解决行为，因为我似乎无法弄清楚测试和真实案例之间的区别。

Answer 1

可能是创建一个csv标头，其中包含位置值，所有子字典键的完整列表。这样，所有subdictionary值都可以在其正确的“key”列下写入：

import csv
dic = {"Location1":{"a":1,"b":2,"c":3},"Location2":{"a":4,"b":5,"c":6}, "Location3":{'e':7,'f':8, 'g':9, 'h':10}, "Location4":{'e': 2, 'f': 3, 'g': 4, 'h': 5}}
header = sorted(set(i for b in map(dict.keys, dic.values()) for i in b))
with open('filename.csv', 'w', newline="") as f:
  write = csv.writer(f)
  write.writerow(['location', *header])
  for a, b in dic.items():
     write.writerow([a]+[b.get(i, '') for i in header])

输出：

location,a,b,c,e,f,g,h
Location1,1,2,3,,,,
Location2,4,5,6,,,,
Location3,,,,7,8,9,10
Location4,,,,2,3,4,5

Answer 2

您可以使用pandas来完成它。

import pandas as pd
dic = {"Location1":{"a":1,"b":2,"c":3},"Location2":{"a":4,"b":5,"c":6}, "Location3":{'e':7,'f':8, 'g':9, 'h':10}, "Location4":{'e': 2, 'f': 3, 'g': 4, 'h': 5}}
pd.DataFrame.from_dict(dic, orient='index').to_csv('temp.csv')

输出：

 ,a,b,c,e,f,g,h
 Location1,1.0,2.0,3.0,,,,
 Location2,4.0,5.0,6.0,,,,
 Location3,,,,7.0,8.0,9.0,10.0
 Location4,,,,2.0,3.0,4.0,5.0

将嵌套字典写入csv

2 个答案: