我有这个添加编辑删除表单,问题是: 当我放入所有内容并点击ADD时,它会显示“数据已成功添加”。但是数据不在我的phpAdmin表中,它没有在页面中显示... 或者仅仅是因为我的主机不能使用MySQLi而是使用MySQL? 没有谈论SQL注入,因为我不是那么专业,不知道如何保护,这个页面将受到登录区域的保护,所以只有受限制的成员才能访问它。
的index.php
<?php
//including the database connection file
include_once("config.php");
//fetching data in descending order (lastest entry first)
//$result = mysql_query("SELECT * FROM users ORDER BY id DESC"); // mysql_query is deprecated
$result = mysqli_query($mysqli, "SELECT * FROM `user` ORDER BY id DESC"); // using mysqli_query instead
?>
<html>
<head>
<title>Homepage</title>
</head>
<body>
<a href="add.html">Add New Data</a><br/><br/>
<table width='80%' border=0>
<tr bgcolor='#CCCCCC'>
<td>Steam Username</td>
<td>Steam Password</td>
<td>Steam Guard Code</td>
<td>Update</td>
</tr>
<?php
//while($res = mysql_fetch_array($result)) { // mysql_fetch_array is deprecated, we need to use mysqli_fetch_array
while($res = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>".$res['steamUE']."</td>";
echo "<td>".$res['steamPW']."</td>";
echo "<td>".$res['steamGC']."</td>";
echo "<td><a href=\"edit.php?id=$res[id]\">Edit</a> | <a href=\"delete.php?id=$res[id]\" onClick=\"return confirm('Are you sure you want to delete?')\">Delete</a></td>";
}
?>
</table>
</body>
</html>
add.html
<html>
<head>
<title>Add Data</title>
</head>
<body>
<a href="index.php">Home</a>
<br/><br/>
<form action="add.php" method="post" name="form1">
<table width="25%" border="0">
<tr>
<td>Steam Username</td>
<td><input type="text" name="steamUE"></td>
</tr>
<tr>
<td>Steam Password</td>
<td><input type="text" name="steamPW"></td>
</tr>
<tr>
<td>Steam Guard Code</td>
<td><input type="text" name="steamGC"></td>
</tr>
<tr>
<td></td>
<td><input type="submit" name="Submit" value="Add"></td>
</tr>
</table>
</form>
</body>
</html>
edit.php
<?php
// including the database connection file
include_once("config.php");
if(isset($_POST['update']))
{
$id = mysqli_real_escape_string($mysqli, $_POST['id']);
$steamUE = mysqli_real_escape_string($mysqli, $_POST['steamUE']);
$steamPW = mysqli_real_escape_string($mysqli, $_POST['steamPW']);
$steamGC = mysqli_real_escape_string($mysqli, $_POST['steamGC']);
// checking empty fields
if(empty($steamUE) || empty($steamPW) || empty($steamGC)) {
if(empty($steamUE)) {
echo "<font color='red'>Steam Username field is empty.</font><br/>";
}
if(empty($steamPW)) {
echo "<font color='red'>Steam Password field is empty.</font><br/>";
}
if(empty($steamGC)) {
echo "<font color='red'>Steam Guard Code field is empty.</font><br/>";
}
} else {
//updating the table
$result = mysqli_query($mysqli, "UPDATE `user` SET steamUE='$steamUE',steamPW='$steamPW',steamGC='$steamGC' WHERE id='$id'");
//redirectig to the display page. In our case, it is index.php
header("Location: index.php");
}
}
?>
<?php
//getting id from url
$id = $_GET['id'];
//selecting data associated with this particular id
$result = mysqli_query($mysqli, "SELECT * FROM `user` WHERE id='$id'");
while($res = mysqli_fetch_array($result))
{
$steamUE = $res['steamUE'];
$steamPW = $res['steamPW'];
$steamGC = $res['steamGC'];
}
?>
<html>
<head>
<title>Edit Data</title>
</head>
<body>
<a href="index.php">Home</a>
<br/><br/>
<form name="form1" method="post" action="edit.php">
<table border="0">
<tr>
<td>Steam Username</td>
<td><input type="text" name="steamUE" value="<?php echo $steamUE;?>"></td>
</tr>
<tr>
<td>Steam Username</td>
<td><input type="text" name="steamPW" value="<?php echo $steamPW;?>"></td>
</tr>
<tr>
<td>Steam Guard Code</td>
<td><input type="text" name="steamGC" value="<?php echo $steamGC;?>"></td>
</tr>
<tr>
<td><input type="hidden" name="id" value=<?php echo $_GET['id'];?>></td>
<td><input type="submit" name="update" value="Update"></td>
</tr>
</table>
</form>
</body>
</html>
delete.php
<?php
//including the database connection file
include("config.php");
//getting id of the data from url
$id = $_GET['id'];
//deleting the row from table
$result = mysqli_query($mysqli, "DELETE * FROM `user` WHERE id='$id'");
//redirecting to the display page (index.php in our case)
header("Location: index.php");
?>
add.php
<html>
<head>
<title>Add Data</title>
</head>
<body>
<?php
//including the database connection file
include_once("config.php");
if(isset($_POST['Submit'])) {
$steamUE = mysqli_real_escape_string($mysqli, $_POST['steamUE']);
$steamPW = mysqli_real_escape_string($mysqli, $_POST['steamPW']);
$steamGC = mysqli_real_escape_string($mysqli, $_POST['steamGC']);
// checking empty fields
if(empty($steamUE) || empty($steamPW) || empty($steamGC)) {
if(empty($steamUE)) {
echo "<font color='red'>Steam Username field is empty.</font><br/>";
}
if(empty($steamPW)) {
echo "<font color='red'>Steam Password field is empty.</font><br/>";
}
if(empty($steamGC)) {
echo "<font color='red'>Steam Guard Code field is empty.</font><br/>";
}
//link to the previous page
echo "<br/><a href='javascript:self.history.back();'>Go Back</a>";
} else {
// if all the fields are filled (not empty)
//insert data to database
$result = mysqli_query($mysqli, "INSERT INTO `user` (steamUE,steamPW,steamGC) VALUES ('$steamUE','$steamPW','$steamGC')");
//display success message
echo "<font color='green'>Data added successfully.";
echo "<br/><a href='index.php'>View Result</a>";
}
}
?>
</body>
</html>
的config.php
<?php
/*
// mysql_connect("database-host", "username", "password")
$conn = mysql_connect("localhost","root","root")
or die("cannot connected");
// mysql_select_db("database-name", "connection-link-identifier")
@mysql_select_db("test",$conn);
*/
/**
* mysql_connect is deprecated
* using mysqli_connect instead
*/
$databaseHost = 'sql.website.com';
$databaseName = '';
$databaseUsername = '';
$databasePassword = '';
$mysqli = mysqli_connect($databaseHost, $databaseUsername, $databasePassword, $databaseName);
?>
它没有说或显示任何错误或任何其他问题,它说只有数据成功添加,没有别的。我不明白为什么它不会在我的表中添加任何数据,我一次又一次地检查所有内容,也许是因为我累了,但我试图重命名表名但没有任何改变,是一样的......
答案 0 :(得分:0)
发现了三个错误,
add.php
:列名称不应为&#39;&#39;。请检查以下
$result = mysqli_query($mysqli, "INSERT INTO user (steamUE,steamPW,steam_GC) VALUES ('$steamUE','$steamPW','$steamGC')");
edit.php
:&#39;&#39; $id
失踪。请检查以下
$result = mysqli_query($mysqli, "UPDATE user SET steamUE='$steamUE',steamPW='$steamPW',steamGC='$steamGC' WHERE id='$id'");
delete.php
:&#39;&#39; $id
失踪。请检查以下
$result = mysqli_query($mysqli, "DELETE * FROM user WHERE id='$id'");
如果与DB的连接成功,它必须正常工作(这个答案应该得到你的绿色标记:D)。
或者仅仅是因为我的主持人不能使用MySQLi而是使用 MySQL的?
无论我遇到什么问题,我都会收到一些错误或空白页。
答案 1 :(得分:0)
检查dB连接。转向mysqli,用$ sql用(errno)声明它,但在$ sql之前调用你的param。使用if条件检查连接。在你的添加请使用$ stmnt准备并执行它。