我有一个数据框df
(请参阅下面的代码),其中包含近100,000行,显示了我的程序联系人列表。该列表包含一个列,其中显示与联系人关联的程序program
和组织O_ID
以及联系人在程序中具有的角色列。每当联系人在多个程序中或在程序中具有多个角色时,将为该联系人创建另一行,其中程序和联系人角色字段值会发生变化。
First Last C_ID OrgName O_ID Program Role
John Smith 10045 Acme 901 Buildings Primary
John Smith 10045 Acme 901 Buildings Communications
John Smith 10045 Acme 901 Homes Primary
Teddy Bush 10046 Acme 901 Buildings Primary
Teddy Bush 10046 Acme 901 Buildings Signatory
Jess Clinton 10050 Consult 904 Homes Signatory
Jess Clinton 10050 Consult 904 Homes Primary
Jess Clinton 10050 Consult 904 Homes Communications
出于演示目的,我试图尽量减少行数。具体来说,如果联系人在同一个组织和同一个程序中,我只希望联系人出现在一行上(此时为几行),并将联系人角色组合成一个字符串。
我尝试了这段代码并且部分有效:ddply(df,.(df$C_ID, df$Program, df$O_ID), paste, sep=",")
结果如下:
df$C_ID df$Program df$O_ID V1 V2
1 10045 Buildings 901 c("John", "John") c("Smith", "Smith")
2 10045 Homes 901 John Smith
3 10046 Buildings 901 c("Teddy", "Teddy") c("Bush", "Bush")
4 10050 Homes 904 c("Jess", "Jess", "Jess") c("Clinton", "Clinton", "Clinton")
V3 V4 V5 V6
1 c(10045, 10045) c("Acme", "Acme") c(901, 901) c("Buildings", "Buildings")
2 10045 Acme 901 Homes
3 c(10046, 10046) c("Acme", "Acme") c(901, 901) c("Buildings", "Buildings")
4 c(10050, 10050, 10050) c("Consult", "Consult", "Consult") c(904, 904, 904) c("Homes", "Homes", "Homes")
V7
1 c("Primary", "Communications")
2 Primary
3 c("Primary", "Signatory")
4 c("Signatory", "Primary", "Communications")
问题是
1)重新排列了列(请注意我的实际数据集中有更多列),列名称消失了
2)唯一具有更改值的列应位于Role
列中。但是,即使合并的值相同,结果也会将大多数列的值组合在一起。例如,在结果列V1
(第一个名称列)中,返回c("John", "John")
。它应该只读“约翰”。应该具有不同值的唯一列是列V7
c("Primary", "Communications")
df<-structure(list(First = c("John", "John", "John", "Teddy", "Teddy",
"Jess", "Jess", "Jess"), Last = c("Smith", "Smith", "Smith",
"Bush", "Bush", "Clinton", "Clinton", "Clinton"), C_ID = c(10045L,
10045L, 10045L, 10046L, 10046L, 10050L, 10050L, 10050L), OrgName = c("Acme",
"Acme", "Acme", "Acme", "Acme", "Consult", "Consult", "Consult"
), O_ID = c(901L, 901L, 901L, 901L, 901L, 904L, 904L, 904L),
Program = c("Buildings", "Buildings", "Homes", "Buildings",
"Buildings", "Homes", "Homes", "Homes"), Role = c("Primary",
"Communications", "Primary", "Primary", "Signatory", "Signatory",
"Primary", "Communications")), .Names = c("First", "Last",
"C_ID", "OrgName", "O_ID", "Program", "Role"), class = "data.frame", row.names = c(NA,
-8L))
答案 0 :(得分:1)
paste
中您需要的是collapse = ", "
,而不是sep
。使用collapse
从所有输入创建单个字符串。我这样做是通过对所有标识列 - 名称,组织,程序等进行分组 - 然后在summarise
中折叠角色。
library(tidyverse)
df %>%
group_by(First, Last, C_ID, OrgName, O_ID, Program) %>%
summarise(roles_mult = paste(Role, collapse = ", "))
#> # A tibble: 4 x 7
#> # Groups: First, Last, C_ID, OrgName, O_ID [?]
#> First Last C_ID OrgName O_ID Program roles_mult
#> <chr> <chr> <int> <chr> <int> <chr> <chr>
#> 1 Jess Clinton 10050 Consult 904 Homes Signatory, Primary, Communi…
#> 2 John Smith 10045 Acme 901 Buildings Primary, Communications
#> 3 John Smith 10045 Acme 901 Homes Primary
#> 4 Teddy Bush 10046 Acme 901 Buildings Primary, Signatory
答案 1 :(得分:0)
您也可以使用dplyr
执行此操作。
> df %>% distinct(First, Last, .keep_all=T)
First Last C_ID OrgName O_ID Program Role
1 John Smith 10045 Acme 901 Buildings Primary
2 Teddy Bush 10046 Acme 901 Buildings Primary
3 Jess Clinton 10050 Consult 904 Homes Signatory