Question

我正在对监视器进行编码，以便相互排除对std::list方法的访问权限我现在拥有的基本上是这样的：



list<int> l;
class monitor{
    public:
    void m_add(int x){
        //lock use of m_remove
        //lock use of m_add
        l.push_back(x);
        //unlock use of m_add
        //unlock use of m_remove
    }
    void m_remove(int x){
        //lock use of m_remove
        //lock use of m_contains
        //lock use of m_add
        l.remove(x);
        //unlock use of m_add
        //unlock use of m_contains
        //unlock use of m_remove
    }
    bool m_contains(int x){
        //lock use of m_remove
        bool found = find(l.begin(), l.end(), x) != l.end();
        //unlock use of m_remove
        return found;
    }
    private:
    mutex mtx_remove;
    mutex mtx_add;
    mutex mtx_contains;
};

list<int> l; class monitor{ public: void m_add(int x){ //lock use of m_remove //lock use of m_add l.push_back(x); //unlock use of m_add //unlock use of m_remove } void m_remove(int x){ //lock use of m_remove //lock use of m_contains //lock use of m_add l.remove(x); //unlock use of m_add //unlock use of m_contains //unlock use of m_remove } bool m_contains(int x){ //lock use of m_remove bool found = find(l.begin(), l.end(), x) != l.end(); //unlock use of m_remove return found; } private: mutex mtx_remove; mutex mtx_add; mutex mtx_contains; };

在main函数内部，我创建了一个运行add函数的线程，例如我收到了错误

thread t(m.m_add, 1);

我理解（通过查看此处的其他答案）我应该在error: invalid use of non-static member function中运行线程并将所有方法声明为静态，但我需要按顺序实例化thread t(&monitor::m_add, 1);的对象创建互斥锁（或锁，或其他）并在main的范围内将它们设为私有。

此案例最合适的解决方案是什么？如果只能在监视器类的范围内访问锁定会很有趣（顺便说一句，我还打算将monitor放在监视器类中。）

Answer 1

您的线程功能必须是静态的。要从线程访问成员函数，请在创建时将指向对象的指针传递给线程函数。

将monitor方法作为线程参数c ++传递

1 个答案: