使用另一个表中的数据更新一个表

时间:2011-02-18 02:00:00

标签: sql database

表1:

id    name    desc
-----------------------
1     a       abc
2     b       def
3     c       adf

表2:

id    name    desc
-----------------------
1     x       123
2     y       345

如何运行 sql update 查询,该查询可以使用相同的ID更新表1中的表2的名称和desc?所以我得到的最终结果是

表1:

id    name    desc
-----------------------
1     x       123
2     y       345
3     c       adf

如何做到这一点:

  • SQL Server
  • MySQL的
  • 的PostgreSQL
  • 甲骨文

5 个答案:

答案 0 :(得分:74)

对于MySql:

UPDATE table1 JOIN table2 
    ON table1.id = table2.id
SET table1.name = table2.name,
    table1.`desc` = table2.`desc`

对于Sql Server:

UPDATE   table1
SET table1.name = table2.name,
    table1.[desc] = table2.[desc]
FROM table1 JOIN table2 
   ON table1.id = table2.id

答案 1 :(得分:21)

Oracle 11g R2:

create table table1 (
  id number,
  name varchar2(10),
  desc_ varchar2(10)
);

create table table2 (
  id number,
  name varchar2(10),
  desc_ varchar2(10)
);

insert into table1 values(1, 'a', 'abc');
insert into table1 values(2, 'b', 'def');
insert into table1 values(3, 'c', 'ghi');

insert into table2 values(1, 'x', '123');
insert into table2 values(2, 'y', '456');

merge into table1 t1
using (select * from table2) t2
on (t1.id = t2.id)
when matched then update set t1.name = t2.name, t1.desc_ = t2.desc_;

select * from table1;

        ID NAME       DESC_
---------- ---------- ----------
         1 x          123
         2 y          456
         3 c          ghi

另见Oracle - Update statement with inner join

答案 2 :(得分:8)

UPDATE table1
SET 
`ID` = (SELECT table2.id FROM table2 WHERE table1.`name`=table2.`name`)

答案 3 :(得分:7)

尝试以下代码。它对我有用....

UPDATE TableOne 
SET 
field1 =(SELECT TableTwo.field1 FROM TableTwo WHERE TableOne.id=TableTwo.id),
field2 =(SELECT TableTwo.field2 FROM TableTwo WHERE TableOne.id=TableTwo.id)
WHERE TableOne.id = (SELECT  TableTwo.id 
                             FROM   TableTwo 
                             WHERE  TableOne.id = TableTwo.id) 

答案 4 :(得分:1)

使用以下查询块根据ID更新Table1和Table2:

UPDATE Table1, Table2 
SET Table1.DataColumn= Table2.DataColumn
where Table1.ID= Table2.ID;

这是解决此问题的最简单,最快捷的方法。