我想创建一个新列(即Winning_Time),如下表所示。 Match_state(Winning)中的所有Time_diff将存储在新列 Winning_Time 中。其余行将填充NaN或零。 我怎么能这样做?
gsm_id Goal_Flag Union_Level Team_SR Match_state Time_diff Wining_Time
2462796 First goal Scored Burnley Winning 0 days 00:23:15.00 0 days 00:23:15.00
2462796 First goal Conceded Chelsea Losing 0 days 00:23:15.00 NaN
2462796 Other goals Scored Burnley Winning 0 days 00:15:20.00 0 days 00:15:20.00
2462796 Other goals Conceded Chelsea Losing 0 days 00:15:20.00 NaN
2462796 Other goals Scored Burnley Winning 0 days 00:03:34.00 0 days 00:03:34.00
2462796 Other goals Conceded Chelsea Losing 0 days 00:03:34.00 NaN
2462796 Other goals Scored Chelsea Losing 0 days 00:25:59.00 NaN
2462796 Other goals Conceded Burnley Winning 0 days 00:25:59.00 0 days 25:59.00
2462796 Last goal Scored Chelsea Losing 0 days 00:19:11.00 NaN
2462796 Last goal Conceded Burnley Winning 0 days 00:19:11.00 0 days 00:19:11.00
2462795 First goal Scored City Winning 0 days 01:09:15.00 0 days 01:09:15.00
2462795 First goal Conceded Brighton Losing 0 days 01:09:15.00 NaN
2462795 Last goal Scored City Winning 0 days 00:05:21.00 0 days 00:05:21.00
2462795 Last goal Conceded Brighton Losing 0 days 00:05:21.00 NaN
非常感谢您的建议。
答案 0 :(得分:2)
您可以使用numpy.where
:
df['Winning_Time'] = np.where(df['Match_state'] == 'Winning', df['Time_diff'], np.nan)
在这里,numpy.where
的作用类似于vectorised if / else语句。