每当我导航到这个视图控制器时,由于某种原因,speakText()
中的viewDidLoad
函数不起作用,视图控制器需要很长时间才能加载(当我删除时不是这种情况)那条线)。在该行上方,文本标签的文本被设置为要说出的字符串,并且工作正常。每次调用recordTapped
时,语音合成都能完美运行。但是,它似乎在viewDidLoad
中不起作用。
UPDATE 在分配了语音合成器的视图控制器委托并异步运行该函数之后,我做了一些测试。但是,它不起作用。我将视图控制器设置为初始视图控制器,但它仍然不起作用,因此在导航中不是问题,加载时间仍然很长。
import UIKit
import AVFoundation
class StartViewController: UIViewController, AVAudioRecorderDelegate {
@IBOutlet weak var questionLabel: UILabel!
@IBOutlet weak var recordButton: UIButton!
let synth = AVSpeechSynthesizer()
var myUtterance = AVSpeechUtterance(string: "")
var number = 0
override func viewDidLoad() {
super.viewDidLoad()
synth.delegate? = self as! AVSpeechSynthesizerDelegate
number = 0
DispatchQueue.global(qos: .userInitiated).async {self.speakText(int: number)}
self.number = self.number + 1
}
@IBAction func recordTapped(_ sender: UIButton) {
speakText(int: number)
number = number + 1
}
func speakText(int: Int) {
myUtterance = AVSpeechUtterance(string: "the number is \(int)")
myUtterance.voice = AVSpeechSynthesisVoice(language: "en-AU")
synth.speak(myUtterance)
}
}
答案 0 :(得分:1)
正如我在评论中所说,多线程有效。刚试过自己。下面的工作代码,请测试并确认。依靠单独的线程进行语音总是好的。
if (result instanceOf <SomeSubtype>) {
<SomeSubtype> resultCasted = (<SomeSubtype>) result;
}
加号,要在显示视图时调用语音,请从import UIKit
import AVFoundation
class ViewController: UIViewController {
@IBOutlet weak var questionLabel: UILabel!
@IBOutlet weak var recordButton: UIButton!
var number = 0
@IBAction func recordTapped(_ sender: UIButton) {
questionLabel.text = "\(number)"
speakTest(int: number)
number += 1
}
override func viewDidLoad() {
super.viewDidLoad()
number = 0
questionLabel.text = "\(number)"
DispatchQueue.global(qos: .userInitiated).async {
self.speakTest(int: self.number)
}
// speakTest(int: number)
// Do any additional setup after loading the view, typically from a nib.
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
func speakTest(int: Int) {
let utterance = AVSpeechUtterance(string: "Number is \(int)")
let synth = AVSpeechSynthesizer()
synth.speak(utterance)
}
}
或viewWillAppear()
而不是viewDidAppear()
调用,因为后者在调用时调用一次应用程序在前台。