Question

是否可以使用谓词过滤空值？例如，我有一个看起来像这样的Realm对象：

class CropData: Object  {

@objc dynamic var cropper = ""
@objc dynamic var x: CGFloat = 0.0
@objc dynamic var y: CGFloat = 0.0
@objc dynamic var width : CGFloat = 0.0
@objc dynamic var height: CGFloat = 0.0
@objc dynamic var scaleX: CGFloat = 0.0
@objc dynamic var scaleY: CGFloat = 0.0
@objc dynamic var rotate: CGFloat = 0.0


override static func primaryKey() -> String? {
return "cropper"
}

示例json数据

{"cropper": "","x": "0","y": "0","width": "0","height": "0","scaleX": "0","scaleY": "0","rotate": "0"}

在这个例子中，有没有办法可以过滤或忽略空的＆＃34; cropper＆＃34;属性？

Answer 1

您可以像这样过滤

let realm = try! Realm()
let result = realm.objects(CropData).filter("cropper = %@", <#YOUR VALUE#>)

Answer 2

您可以使用Predicate过滤

使用cropper获取所有对象=＆＃34;＆＃34; ：

let result = realm.objects(CropData.self).filter("cropper = %@", "")

或忽略它

let result = realm.objects(CropData.self).filter("cropper != %@", "")

您可以在此处阅读更多Predicate语法https://developer.apple.com/library/content/documentation/Cocoa/Conceptual/Predicates/Articles/pSyntax.html

过滤Realm对象的属性

2 个答案: