如何在shell脚本中使用sqlplus以下面的列形式获取sql结果。请注意第1列是标题,第2列是行值(只有1行需要显示为无其他匹配。)
STAT_DATE 20180515
SERVER_NAME abcd3363
Hits1 112389
Hits2 659405
而选择命令简单,我得到如下。
STAT_DATE SERVER_NAME Hits1 Hits2
----------- -------------- -------- --------
20180515 abcd3363 112389 659405
答案 0 :(得分:0)
这应该有帮助 -
CREATE TABLE tabl1
(STAT_DATE varchar2(11), SERVER_NAME varchar2(14), Hits1 varchar2(8), Hits2 varchar2(8))
;
INSERT ALL
INTO tabl1 (STAT_DATE, SERVER_NAME, Hits1, Hits2)
VALUES ('20180515', 'abcd3363', '112389', '659405')
SELECT * FROM dual
;
查询 -
select * from tabl1
unpivot (vals for cols in (STAT_DATE as 'STAT_DATE', SERVER_NAME AS 'SERVER_NAME', Hits1 AS 'Hits1', Hits2 AS 'Hits2'));
;
输出 -
COLS VALS
STAT_DATE 20180515
SERVER_NAME abcd3363
Hits1 112389
Hits2 659405