如何在多线程程序中保留线程变量的值

时间:2018-05-15 23:46:04

标签: java multithreading executorservice

我有一个代码,它每5秒生成一个新线程,每个线程会定期打印出一个计数器的值。它最多可以启动10个线程。

以下是代码:

public static void main(String[] args) {
    ScheduledExecutorService task = Executors.newScheduledThreadPool(10);
    AtomicInteger counter = new AtomicInteger(0);
    int i = 0;
    while (i < 10) {
        // sleep 5 seconds
        sleep(5);
        task.scheduleAtFixedRate(() -> {
            String threadName = Thread.currentThread().getName();
            int newCounter = counter.get();
            System.out.println(String.format("[%s] counter = %d" , threadName, newCounter));
        }, 0, 2, TimeUnit.SECONDS);

        counter.getAndIncrement();
        ++i;
    }
}

private static void sleep(int sleepTime) {
    try {
        TimeUnit.SECONDS.sleep(sleepTime);
    } catch (InterruptedException ie) {

    }
}

这是输出:

[pool-1-thread-1] counter = 1
[pool-1-thread-1] counter = 1
[pool-1-thread-2] counter = 1
[pool-1-thread-3] counter = 1
[pool-1-thread-1] counter = 2
[pool-1-thread-2] counter = 2
[pool-1-thread-4] counter = 2
[pool-1-thread-5] counter = 2
[pool-1-thread-3] counter = 2
[pool-1-thread-1] counter = 3
[pool-1-thread-7] counter = 3
[pool-1-thread-6] counter = 3
[pool-1-thread-8] counter = 3
[pool-1-thread-4] counter = 3
[pool-1-thread-9] counter = 3
[pool-1-thread-5] counter = 3
[pool-1-thread-10] counter = 3
[pool-1-thread-1] counter = 4
   .......

我希望每个线程都打印出它的原始值,例如,pool-1-thread-1应该打印出0或1(取决于计数器是先增加还是线程首先开始),所有时间,第二个线程应该持续发出前一个计数器+ 1,如下所示:

[pool-1-thread-1] counter = 1
[pool-1-thread-1] counter = 1
[pool-1-thread-2] counter = 2
[pool-1-thread-3] counter = 3
[pool-1-thread-1] counter = 1
[pool-1-thread-2] counter = 2
[pool-1-thread-4] counter = 4
[pool-1-thread-5] counter = 5
[pool-1-thread-3] counter = 3
[pool-1-thread-1] counter = 1
[pool-1-thread-7] counter = 7
  .......

我的问题是如何让newCounter局部变量在每个线程中保持其原始值。我能想到的方法是在线程安全的哈希表中存储线程名称到其原始值的映射。有没有更清洁的方法来实现这一目标?感谢

1 个答案:

答案 0 :(得分:1)

要将值绑定到特定线程,可以使用ThreadLocal变量。 可以很容易地调整javadoc中的ThreadId示例类来解决您的用例。

public static void main(String[] args) {
    ScheduledExecutorService task = Executors.newScheduledThreadPool(10);
    AtomicInteger counter = new AtomicInteger(0);
    ThreadLocal<Integer> id = ThreadLocal.withInitial(counter::incrementAndGet);
    int i = 0;
    while (i < 10) {
        // sleep 5 seconds
        sleep(5);
        task.scheduleAtFixedRate(() -> {
            String threadName = Thread.currentThread().getName();
            System.out.println(String.format("[%s] counter = %d" , threadName, id.get()));
        }, 0, 2, TimeUnit.SECONDS);

        ++i;
    }
}

private static void sleep(int sleepTime) {
    try {
        TimeUnit.SECONDS.sleep(sleepTime);
    } catch (InterruptedException ie) {

    }
}