我有一个包含1个表和2个子查询的查询。该表是所有客户的列表,1个子查询列出了客户在一段时间内给出的所有报价,而另一个子查询是在同一时间段内为客户预订的所有订单的列表。我要做的是返回一个客户的结果集,给出的报价数量,以及在给定时间段内预订的订单数量。然而,我要归还的只是在一段时间内听取客户的同等报价和订单数量。我觉得我在查询的上下文中遗漏了一些明显的东西,但我无法弄明白。任何帮助,将不胜感激。谢谢。
结果集应如下所示
客户-------行情-------下订单
AAA ---------------- 4 ---------------- 4
BBB ---------------- 9 ---------------- 18
CCC ---------------- 18 ---------------- 9
select
[Customer2].[Name] as [Customer2_Name],
(count( Quotes.UD03_Key3 )) as [Calculated_CustomerQuotes],
(count( Customer_Bookings.OrderHed_OrderNum )) as [Calculated_CustomerBookings]
from Erp.Customer as Customer2
left join (select
[UD03].[Key3] as [UD03_Key3],
[UD03].[Key4] as [UD03_Key4],
[UD03].[Key1] as [UD03_Key1],
[UD03].[Date02] as [UD03_Date02]
from Ice.UD03 as UD03
inner join Ice.UD02 as UD02 on
UD03.Company = UD02.Company
And
CAST(CAST(UD03.Number09 AS INT) AS VARCHAR(30)) = UD02.Key1
left outer join Erp.Customer as Customer on
UD03.Company = Customer.Company
And
UD03.Key1 = Customer.Name
left outer join Erp.SalesTer as SalesTer on
Customer.Company = SalesTer.Company
And
Customer.TerritoryID = SalesTer.TerritoryID
left outer join Erp.CustGrup as CustGrup on
Customer.Company = CustGrup.Company
And
Customer.GroupCode = CustGrup.GroupCode
where (UD03.Key3 <> '0')) as Quotes on
Customer2.Name = Quotes.UD03_Key1
left join (select
[Customer1].[Name] as [Customer1_Name],
[OrderHed].[OrderNum] as [OrderHed_OrderNum],
[OrderDtl].[OrderLine] as [OrderDtl_OrderLine],
[OrderHed].[OrderDate] as [OrderHed_OrderDate]
from Erp.OrderHed as OrderHed
inner join Erp.Customer as Customer1 on
OrderHed.Company = Customer1.Company
And
OrderHed.BTCustNum = Customer1.CustNum
inner join Erp.OrderDtl as OrderDtl on
OrderHed.Company = OrderDtl.Company
And
OrderHed.OrderNum = OrderDtl.OrderNum) as Customer_Bookings on
Customer2.Name = Customer_Bookings.Customer1_Name
where Quotes.UD03_Date02 >= '5/15/2018' and Quotes.UD03_Date02 <= '5/15/2018' and Customer_Bookings.OrderHed_OrderDate >='5/15/2018' and Customer_Bookings.OrderHed_OrderDate <= '5/15/2018'
group by [Customer2].[Name]
答案 0 :(得分:1)
你有几个问题在这里发生。第一个问题是你的代码格式太差,用户看起来很敌意。然后,由于where子句,您将左连接在逻辑上视为内连接。您还具有特定语言格式的日期文字字符串。这应该始终是ANSI格式YYYYMMDD。但在你的情况下,你的两个谓词相互矛盾。 UD03_Date02同时大于和小于同一日期。谢天你有=。但是,如果您的列是日期时间,则您已阻止再次返回任何行(第一个是您的where子句)。你有相同的错误日期逻辑,并加入第二个子查询。
以下是您的查询可能与某些格式相似的内容,以便您可以看到正在发生的事情。请注意我修复了逻辑连接问题。你仍然有日期问题,因为我不知道你想要在那里完成什么。
select
[Customer2].[Name] as [Customer2_Name],
count(Quotes.UD03_Key3) as [Calculated_CustomerQuotes],
count(Customer_Bookings.OrderHed_OrderNum) as [Calculated_CustomerBookings]
from Erp.Customer as Customer2
left join
(
select
[UD03].[Key3] as [UD03_Key3],
[UD03].[Key4] as [UD03_Key4],
[UD03].[Key1] as [UD03_Key1],
[UD03].[Date02] as [UD03_Date02]
from Ice.UD03 as UD03
inner join Ice.UD02 as UD02 on UD03.Company = UD02.Company
And CAST(CAST(UD03.Number09 AS INT) AS VARCHAR(30)) = UD02.Key1
left outer join Erp.Customer as Customer on UD03.Company = Customer.Company
And UD03.Key1 = Customer.Name
left outer join Erp.SalesTer as SalesTer on Customer.Company = SalesTer.Company
And Customer.TerritoryID = SalesTer.TerritoryID
left outer join Erp.CustGrup as CustGrup on Customer.Company = CustGrup.Company
And Customer.GroupCode = CustGrup.GroupCode
where UD03.Key3 <> '0'
) as Quotes on Customer2.Name = Quotes.UD03_Key1
and Quotes.UD03_Date02 >= '20180515'
and Quotes.UD03_Date02 <= '20180515'
left join
(
select
[Customer1].[Name] as [Customer1_Name],
[OrderHed].[OrderNum] as [OrderHed_OrderNum],
[OrderDtl].[OrderLine] as [OrderDtl_OrderLine],
[OrderHed].[OrderDate] as [OrderHed_OrderDate]
from Erp.OrderHed as OrderHed
inner join Erp.Customer as Customer1 on OrderHed.Company = Customer1.Company
And OrderHed.BTCustNum = Customer1.CustNum
inner join Erp.OrderDtl as OrderDtl on OrderHed.Company = OrderDtl.Company
And OrderHed.OrderNum = OrderDtl.OrderNum
) as Customer_Bookings on Customer2.Name = Customer_Bookings.Customer1_Name
and Customer_Bookings.OrderHed_OrderDate >= '20180515'
and Customer_Bookings.OrderHed_OrderDate <= '20180515'
group by [Customer2].[Name]
答案 1 :(得分:0)
COUNT()只会给你一些记录。您希望这两个结果列相等。尝试像这样构建它:
SUM(CASE WHEN Quote.UD03_Key1 IS NOT NULL THEN 1 ELSE 0 END) AS QuoteCount,
SUM(CASE WHEN Customer_Bookings.Customer1_Name IS NOT NULL THEN 1 ELSE 0 END) AS custBookingCount