Question

所以我正在使用Python并且还很新，我需要能够遍历目录中的所有文件夹，所以如果/foo包含/foo/bar和/foo/bar/foo我想列出所有条目。到目前为止，我已经创建了一个在其自己的文件中工作的类，但是当我尝试import时，我收到一条错误，指出TypeError: coercing to Unicode: need string or buffer, builtin_function_or_method found。

在DirTree文件中找到了功能，所以我通过以下方式导入它：

from DirTree import DirTrav

DirList = DirTrav(dir).returnList()

代码可以在下面找到。

import os

class DirTrav:
    DList = []
    dir = ""

    def __init__(self, dirTrav):
        self.dir = dirTrav

    def dirTree(self, start):
        _subFolders = os.listdir(start)
        for f in _subFolders:
            _newFolder = os.path.join(start, f)
            if os.path.isdir( _newFolder):
                self.DList.append(_newFolder)
                self.dirTree(_newFolder)

    def returnList(self):
        self.dirTree(dir)
        return self.DList

Answer 1

使用os.walk()：

for root, dirs, files in os.walk():
    for filename in files:
        # do something with filename (files and will return all files recursively)
        # note f is only filename and not path, use the following (as an example if you wanted to open the file)
        with open(os.path.join(root, filename)) as f:
            for line in f:
                print f
        pass

递归地跟随目录树

1 个答案: