Question

我正在使用pyhive与hive进行交互。

SELECT语句使用此代码顺利进行。

# Import hive module and connect
from pyhive import hive
conn = hive.Connection(host="HOST")
cur = conn.cursor()

# Import pandas
import pandas as pd

# Store select query in dataframe 
all_tables = pd.read_sql("SELECT * FROM table LIMIT 5", conn)
print all_tables

# Using curssor 
cur = conn.cursor()
cur.execute('SELECT * FROM table LIMIT 5')
print cursor.fetchall()

直到这里没有问题。当我想INSERT进入蜂巢时。

我们要说我要执行此查询：INSERT INTO table2 SELECT Col1, Col2 FROM table1;

我试过了：

cur.execute('INSERT INTO table2 SELECT Col1, Col2 FROM table1')

我收到此错误

pyhive.exc.OperationalError: TExecuteStatementResp(status=TStatus(errorCode=1, errorMessage=u'Error while processing statement: FAILED: Execution Error, return code 1 from org.apache.hadoop.hive.ql.exec.tez.TezTask', sqlState=u'08S01', infoMessages=[u'*org.apache.hive.service.cli.HiveSQLException:Error while processing statement: FAILED: Execution Error, return code 1 from org.apache.hadoop.hive.ql.exec.tez.TezTask:28:27', u'org.apache.hive.service.cli.operation.Operation:toSQLException:Operation.java:388', u'org.apache.hive.service.cli.operation.SQLOperation:runQuery:SQLOperation.java:244', u'org.apache.hive.service.cli.operation.SQLOperation:runInternal:SQLOperation.java:279', u'org.apache.hive.service.cli.operation.Operation:run:Operation.java:324', u'org.apache.hive.service.cli.session.HiveSessionImpl:executeStatementInternal:HiveSessionImpl.java:499', u'org.apache.hive.service.cli.session.HiveSessionImpl:executeStatement:HiveSessionImpl.java:475', u'sun.reflect.GeneratedMethodAccessor81:invoke::-1', u'sun.reflect.DelegatingMethodAccessorImpl:invoke:DelegatingMethodAccessorImpl.java:43', u'java.lang.reflect.Method:invoke:Method.java:498', u'org.apache.hive.service.cli.session.HiveSessionProxy:invoke:HiveSessionProxy.java:78', u'org.apache.hive.service.cli.session.HiveSessionProxy:access$000:HiveSessionProxy.java:36', u'org.apache.hive.service.cli.session.HiveSessionProxy$1:run:HiveSessionProxy.java:63', u'java.security.AccessController:doPrivileged:AccessController.java:-2', u'javax.security.auth.Subject:doAs:Subject.java:422', u'org.apache.hadoop.security.UserGroupInformation:doAs:UserGroupInformation.java:1698', u'org.apache.hive.service.cli.session.HiveSessionProxy:invoke:HiveSessionProxy.java:59', u'com.sun.proxy.$Proxy33:executeStatement::-1', u'org.apache.hive.service.cli.CLIService:executeStatement:CLIService.java:270', u'org.apache.hive.service.cli.thrift.ThriftCLIService:ExecuteStatement:ThriftCLIService.java:507', u'org.apache.hive.service.rpc.thrift.TCLIService$Processor$ExecuteStatement:getResult:TCLIService.java:1437', u'org.apache.hive.service.rpc.thrift.TCLIService$Processor$ExecuteStatement:getResult:TCLIService.java:1422', u'org.apache.thrift.ProcessFunction:process:ProcessFunction.java:39', u'org.apache.thrift.TBaseProcessor:process:TBaseProcessor.java:39', u'org.apache.hive.service.auth.TSetIpAddressProcessor:process:TSetIpAddressProcessor.java:56', u'org.apache.thrift.server.TThreadPoolServer$WorkerProcess:run:TThreadPoolServer.java:286', u'java.util.concurrent.ThreadPoolExecutor:runWorker:ThreadPoolExecutor.java:1149', u'java.util.concurrent.ThreadPoolExecutor$Worker:run:ThreadPoolExecutor.java:624', u'java.lang.Thread:run:Thread.java:748'], statusCode=3), operationHandle=None)

如果我在hive中直接执行相同的查询，一切运行良好。有什么想法吗？

注意：我所有的桌子都是外部的

CREATE EXTERNAL TABLE IF NOT EXISTS table ( col1 String, col2 String) stored as orc LOCATION 's3://somewhere' tblproperties ("orc.compress"="SNAPPY");

Answer 1

解决方案是在连接线中添加用户名; conn = hive.Connection(host="HOST", username="USER")

据我所知，hive查询分为多种类型的操作（作业）。在执行简单查询时（ie. SELECT * FROM table）这将从hive Metorore读取数据，而不执行mapReduce作业或执行查询所需的tmp表。但是一旦你切换到更复杂的查询（即使用JOIN），你最终会遇到同样的错误。

文件代码如下所示：

# Import hive module and connect
from pyhive import hive
conn = hive.Connection(host="HOST", username="USER")
cur = conn.cursor()
query = "INSERT INTO table2 SELECT Col1, Col2 FROM table1"
cur.execute(query)

所以也许它需要许可或其他东西..我会更多地搜索这个行为并更新答案。

Answer 2

我不确定如何使用pyhive插入pandas df，但是如果你安装了pyspark，一个选项是你可以转换为spark df并使用pyspark来完成它。

from pyspark.sql import sqlContext
spark_df = sqlContext.createDataFrame(pandas_df)
spark_df.write.mode('append').saveAsTable('database_name.table_name')

Answer 3

您可以使用spark执行以下操作。

from pyspark.sql import sqlContext

# convert the pandas data frame to spark data frame
spark_df = sqlContext.createDataFrame(pandas_df)

# register the spark data frame as temp table
spark_df.registerTempTable("my_temp_table")

# execute insert statement using spark sql
sqlContext,sql("insert into hive_table select * from my_temp_table")

这会将data frame中的数据插入到hive表格中。

希望这有助于你

插入Hive使用Pyhive调用错误

3 个答案: